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irina [24]
3 years ago
10

A pulsar is a rapidly rotating neutron star. The Crab nebula pulsar in the constellation Taurus has a period of 33.5\times 10^{-

3}~\text{s}33.5×10 ​−3 ​​ s, radius 10.0 km, and mass 2.8\times 10^{30}~\text{kg}2.8×10 ​30 ​​ kg. The pulsar’s rotational period will increase over time due to the release of electromagnetic radiation, which doesn’t change its radius but reduces its rotational energy. What is the angular momentum of the pulsar?
Physics
1 answer:
joja [24]3 years ago
8 0

Answer:

5.25\cdot 10^{40} kg m^2/s

Explanation:

The angular momentum of the pulsar is given by:

L=m\omega r^2

where

m=2.8\cdot 10^{30} kg is the mass of the pulsar

r = 10.0 km = 1\cdot 10^4 m is the radius

\omega is the angular speed

Given the period of the pulsar, T=33.5\cdot 10^{-3} s, the angular speed is given by

\omega=\frac{2\pi}{T}=\frac{2 \pi}{33.5\cdot 10^{-3}s}=187.5 rad/s

And so, the angular momentum is

L=m\omega r^2=(2.8\cdot 10^{30}kg)(187.5 rad/s)(1\cdot 10^4 m)^2=5.25\cdot 10^{40} kg m^2/s

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A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but had twice as much mass,
fomenos

Answer:

The momentum would be doubled

Explanation:

The magnitude of the momentum of the freight train is given by:

p=mv

where

m is the mass of the train

v is its speed

In this problem, we have that the speed of the train is unchanged, while the mass of the train is doubled:

m'=2m

therefore, the new momentum is

p'=m'v=(2m)v=2(mv)=2p

so, the momentum has also doubled.

7 0
3 years ago
Q1: A runner is jogging in a straight line at a steady vr= 6.8 km/hr. When the runner is L= 2.4 km from the finish line, a bird
serious [3.7K]

Answer:

Q1: 3.2km

Q2: 4.8K

Explanation:

Q1:

So db is the distance of bird, and dr is the distance of runner

db = 2vr  and the distance of bird is going to be 2 times greater than the runner.

formulas: db = 2vr & db = 2dr

  1. db = 2dr
  2. L + (L - x) = 2x
  3. 2L - x = 2x
  4. 2L = 3x
  5. x = \frac{2}{3}L

Insert it in x = \frac{2}{3}L

\frac{2}{3}(2.4km) = 1.6km

Now we use formula db = 2dr

  1. db = 2L - x
  2. db = 2(2.4km) - 1.6km
  3. <u>db = 3.2km</u>

Q2:

Formulas: Vr = L /Δt & Vb = db/Δt

  1. Vr = L/ Δt ⇒ Δt = \frac{L}{Vr}
  2. \frac{2.4km}{6.8km/hr}
  3. \frac{6}{17}hr

(Km cancel each other)

  1. Vb = db/Δt ⇒ db = VbΔt
  2. 13.6km/hr(\frac{6}{17}hr )
  3. <u>4.8km</u>

(hr cancel each other)

Hope it helps you :)

6 0
3 years ago
Need help with this question
Alika [10]

Answer:

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Digital art

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Digital art is an artistic work or practice that uses digital technology as part of the creative or presentation process. Since the 1960s, various names have been used to describe the process, including computer art and multimedia art.[1] Digital art is itself placed under the larger umbrella term new media art.[2][3]

Maurizio Bolognini, Programmed Machines (Nice, France, 1992–97). An installation at the intersection of digital art and conceptual art (computers are programmed to generate flows of random images which nobody would see).

The image of the computer virus Chernobyl, created by Ukrainian new media artist Stepan Ryabchenko in 2011.

Irrational Geometrics digital art installation 2008 by Pascal Dombis

Joseph Nechvatal birth Of the viractual 2001 computer-robotic assisted acrylic on canvas

The Cave Automatic Virtual Environment at the University of Illinois, Chicago

After some initial resistance,[4] the impact of digital technology has transformed activities such as painting, drawing, sculpture and music/sound art, while new forms, such as net art, digital installation art, and virtual reality, have become recognized artistic practices.[5] More generally the term digital artist is used to describe an artist who makes use of digital technologies in the production of art. In an expanded sense, "digital art" is contemporary art that uses the methods of mass production or digital media.[6]

Lillian Schwartz's Comparison of Leonardo's self portrait and the Mona Lisa based on Schwartz's Mona Leo. An example of a collage of digitally manipulated photographs

The techniques of digital art are used extensively by the mainstream media in advertisements, and by film-makers to produce visual effects. Desktop publishing has had a huge impact on the publishing world, although that is more related to graphic design. Both digital and traditional artists use many sources of electronic information and programs to create their work.[7] Given the parallels between visual and musical arts, it is possible that general acceptance of the value of digital visual art will progress in much the same way as the increased acceptance of electronically produced music over the last three decades.[8]

Digital art can be purely computer-generated (such as fractals and algorithmic art) or taken from other sources, such as a scanned photograph or an image drawn using vector graphics software using a mouse or graphics tablet.[9] Though technically the term may be applied to art done using other media or processes and merely scanned in, it is usually reserved for art that has been non-trivially modified by a computing process (such as a computer program, microcontroller or any electronic system capable of interpreting an input to create an output); digitized text data and raw audio and video recordings are not usually considered digital art in themselves, but can be part of the larger project of computer art and information art.[10] Artworks are considered digital painting when created in similar fashion to non-digital paintings but using software on a computer platform and digitally outputting the

6 0
3 years ago
Question 1 (1 point)
deff fn [24]

Answer:

Travelled 18 km, they are 6 km from home.

Explanation:

12/2 (halfway) is 6km. So, 6 + 12 would be 18 km, total amount travelled. The total distance of the trip would be 24 km (12 km out, 12km back) if they travelled 12+6 (18km) then they only have 6 km more to go.

5 0
3 years ago
A hiker travels south along a straight line path for 1.5 hours with an average velocity of 0.75 km/hr, then travels south for 2.
ANTONII [103]
Distance travelled in south direction= 1.5hr*0.75km/hr= 1.125km
Distance travlled in north direction= 0.90*2.5=2.25
Net displacement = 2.25-1.125= 1.125 to the north
7 0
3 years ago
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