Answer:
y = 17 m
Explanation:
For this projectile launch exercise, let's write the equation of position
x = v₀ₓ t
y =
t - ½ g t²
let's substitute
45 = v₀ cos θ t
10 = v₀ sin θ t - ½ 9.8 t²
the maximum height the ball can reach where the vertical velocity is zero
v_{y} = v_{oy} - gt
0 = v₀ sin θ - gt
0 = v₀ sin θ - 9.8 t
Let's write our system of equations
45 = v₀ cos θ t
10 = v₀ sin θ t - ½ 9.8 t²
0 = v₀ sin θ - 9.8 t
We have a system of three equations with three unknowns for which it can be solved.
Let's use the last two
v₀ sin θ = 9.8 t
we substitute
10 = (9.8 t) t - ½ 9.8 t2
10 = ½ 9.8 t2
10 = 4.9 t2
t = √ (10 / 4.9)
t = 1,429 s
Now let's use the first equation and the last one
45 = v₀ cos θ t
0 = v₀ sin θ - 9.8 t
9.8 t = v₀ sin θ
45 / t = v₀ cos θ
we divide
9.8t / (45 / t) = tan θ
tan θ = 9.8 t² / 45
θ = tan⁻¹ ( 9.8 t² / 45
)
θ = tan⁻¹ (0.4447)
θ = 24º
Now we can calculate the maximum height
v_y² =
- 2 g y
vy = 0
y = v_{oy}^2 / 2g
y = (20 sin 24)²/2 9.8
y = 3,376 m
the other angle that gives the same result is
θ‘= 90 - θ
θ' = 90 -24
θ'= 66'
for this angle the maximum height is
y = v_{oy}^2 / 2g
y = (20 sin 66)²/2 9.8
y = 17 m
thisis the correct
Answer:
B
Explanation:
You always want to test as many samples as possible
Answer:
0 N
Explanation:
Applying,
F = qvBsin∅................. Equation 1
Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.
From the question,
Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°
Substitute these values into equation 1
F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)
Since sin0° = 0,
Therefore,
F = 0 N
Answer:
1. Why is Jupiter's rotation dangerous for human survivability?
<h2>=> </h2>
<em><u>Jupiter is the fastest rotating planet in our solar system. One day lasts about 9.5 Earth hours. This creates powerful winds that can whip around the planet at more than 300 mph. About 75 miles below the clouds, you reach the limit of human exploration.</u></em>
2 .Why is Jupiter's planet axis tilt an issue for human survivability?
<h2>=></h2>
<em><u>Jupiter, like Venus, has an axial tilt of only 3 degrees, so there is literally no difference between the seasons. ... The length of each season is roughly three years. Jupiter is the fastest spinning planet in our Solar System, which causes the planet to flatten at the poles and bulge at the </u></em><em><u>equator.</u></em>
3.Why is the diameter of Jupiter an issue for human survivability?
<h2>=></h2>
<em><u>Since </u></em><em><u>,</u></em><em><u>The </u></em><em><u>Jupiter </u></em><em><u>is </u></em><em><u>so </u></em><em><u>huge </u></em><em><u>in </u></em><em><u>mass</u></em><em><u> </u></em><em><u>,</u></em><em><u>The </u></em><em><u>central</u></em><em><u> </u></em><em><u>force</u></em><em><u> </u></em><em><u>toward</u></em><em><u> </u></em><em><u>the </u></em><em><u>centre </u></em><em><u>will </u></em><em><u>be </u></em><em><u>high</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>we'll</u></em><em><u> </u></em><em><u>be </u></em><em><u>forced</u></em><em><u> </u></em><em><u>toward</u></em><em><u> </u></em><em><u>it </u></em><em><u>causing</u></em><em><u> </u></em><em><u>Several</u></em><em><u> </u></em><em><u>problems</u></em><em><u>.</u></em>