The electric field 30cm from a van de Graaff generator is measured to be 28,300N/C. What is the charge of the van de Graaf?

a sensor light installed on the edge of a home can detect motion for a distance of 50 feet in front and with a range of motion o

Dvinal [7]

Answer:

4363.3231 feets²

Explanation:

Given that :

Distance, r = 50 ft

θ = 200°

The arc length of area covered :

Arc length = θ/360° * πr²

Arc length = (200/360) * 50 ft ^2 * π

Arc length = 0.5555555 * 2500 * π

Arc length = 4363.3231 feets²

7 0

3 years ago

Can any one help pls

Paraphin [41]

Answer:

A and D are correct as they reduce GHG emissions while maintaining people's standard of living.

7 0

3 years ago

Read 2 more answers

How long does it take the earth to rotate?

zubka84 [21]

It takes Earth 23 hours and 56 minutes to rotate. To be accurate.
Or you can just say 24 hours.
HOPE THIS HELPS YOU! ^_^

3 0

4 years ago

Read 2 more answers

A long, thin solenoid has 950 turns per meter and radius 3.00 cm. The current in the solenoid is increasing at a uniform rate of

REY [17]

Answer:

Part a)

$E = 0.188 \times 10^{-3} N/CPart b)[tex]E = 0.376 \times 10^{-3}$ N/C

Explanation:

As we know that the magnetic field near the center of the solenoid is given as

$B = \mu_0 ni$

Also we know by equation of Faraday's law

EMF induced in the closed loop will be equal to rate of change in magnetic flux

so we have

$EMF = A\frac{dB}{dt}$

so we have

$\int E. dL = \pi r^2 (\mu_0 n \frac{di}{dt})$

$E. (2\pi r) = \pi r^2 (\mu_0 n \frac{di}{dt})$

$E = \frac{\mu_0 n r}{2} \frac{di}{dt}$

Part a)

At r = 0.500 cm

we have

$E = \frac{4\pi \times 10^{-7} (950) (0.500 \times 10^{-2})}{2}(63)$

$E = 0.188 \times 10^{-3} N/C$

Part b)

At r = 1.00 cm

we have

$E = \frac{4\pi \times 10^{-7} (950) (1.00 \times 10^{-2})}{2}(63)$

$E = 0.376 \times 10^{-3}$ N/C

5 0

3 years ago

Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use the given data to const

Fantom [35]

Answer:

The 5-number summary is

1. Median = 0.93 W/kg

2. Lower quartile = 0.69 W/kg

3. Upper quartile = 1.16 W/kg

4. Minimum value = 0.54 W/kg

5. Maximum value = 1.42 W/kg

Explanation:

We are given the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones.

1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57

What is 5-number summary?

A 5-number summary refers to a box plot that basically shows 5 statistical characteristics of a data set.

These statistical characteristics are:

1. Median

2. Lower quartile

3. Upper quartile

4. Minimum value

5. Maximum value

1. Median:

Arrange the data in ascending order

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

(n+1)/2 gives the median value of the data set.

(11 + 1)/2 = 6th position

Therefore, 0.93 W/kg is the median of the data set.

2. Lower quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The lower quartile is the median of the lower half of the data set.

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

The median is 6/2 = 3rd position

Therefore, the lower quartile of the data set is 0.69 W/kg

3. Upper quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The upper quartile is the median of the lower half of the data set.

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The median is 6/2 = 3rd position

Therefore, the upper quartile of the data set is 1.16 W/kg

4. Minimum value:

The minimum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the minimum value of the data set is 0.54 W/kg

5. Maximum value

The maximum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the maximum value of the data set is 1.42 W/kg

The box plot is illustrated in the attached diagram.

6 0

3 years ago