Ca₁₀(PO₄)₆(OH)₂ or Ca(OH)₂·3Ca₃(PO₄)₂
PO₄³⁻ phosphate ion
OH⁻ oxyhydroxide ion
Ca²⁺ calcium ion
10*(+2) + 6*(-3) + 2*(-1) = 0
10Ca²⁺ 6PO₄³⁻ 2OH⁻
Answer:
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Answer:
i think maybe 94.99201599999999
Explanation:
Answer: The new concentration of a solution of 
is 0.2 M 10.0 mL of a 2.0 M solution is diluted to 100 mL.
Explanation:
Given: 
= 10.0 mL, 
= 2.0 M
= 100 mL, 
= ?
Formula used to calculate the new concentration is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the new concentration of a solution of is 0.2 M 10.0 mL of a 2.0 M solution is diluted to 100 mL.
Answer:
Pressure = 4313.43mmHg
Explanation:
P1 = ?
V1 = 0.335L
V2 = 1700mL =1700*10^-3L = 1.7L
P2 = 850mmhg
From Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.
P = k / v
K = pv. P1V1 = P2V2 = P3V3 =........=PnVn
P1V1 = P2V2
Solve for P1,
P1 = (P2*V2) / V1
P1 = (850 * 1.7) / 0.335
P1 = 4313.43mmHg
The pressure of the gas was 4313.43mmHg
