If the totaling of bromine to cis-cinnamic acid uses the
same mechanism or device as the addition to trans-cinnamic acid, addition of
bromine only transpires on the top (syn) and not the bottommost face (anti). Therefore,
bromine added to cis-cinnamic only adds to the same face (syn addition) as a
result producing only threo dibromides.
1. Synthesis
2. Decomposition
3. Displacement
4. Acid-base/ Neutralization,
5. Combustion
Redox, Precipitation
I think it is D
Hope this help you?
NaBr < H3O+1 = OH-1 < Na^+1 = Br^-1 < H2O
<span>Least is NaBr (100% dissolved so no NaBr remains, only Na^+1 and Br^-1 </span>
<span>H2O yields 10^-7 M H3O^+1 and 10^-7 M OH^-1 (Kw = 1x10^-14 = [H3O+][OH-] </span>
<span>Na^+1 and Br^-1 will bothe be 0.1 M </span>
<span>H2O is slightly less that 1000 g / L in a 0.1 M NaBr solution, so its concentration is about 55.5 M</span>