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madreJ [45]
2 years ago
13

How far will a runner travel if she had an average speed of 10 km/hour and runs for 2.1 hours?

Physics
2 answers:
Rasek [7]2 years ago
8 0
10 Km.
S= Speed
D= distance 
T= time

S= d/t
but since you are solving for "d" the equation is d=st so you plug in 10 km/h for speed and 2.1 hours for time and just multiply them. The hours cancel out so you are left with 10km.
Finger [1]2 years ago
4 0
Um I think you need to multiply 10 km by 2.1
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Answer:

The value is  KE_b =0.710 \ J

Explanation:

From the question we are told that

   The mass  of the bullet is m_b  = 5.00 \ g  = 0.005 \  kg

  The mass  of the wood is  m_w =  900 \  g  =  0.90\  kg

   The height attained by the combined mass is  h =  8.0 \ cm  =  0.08 \ m

Generally according to the law of energy conservation    

    KE _b  =  PE_c

Here KE_b is the kinetic energy of the bullet before collision.

and PE_c is the  potential  energy of the combined mass of bullet and wood at the height h which is mathematically represented as

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3 0
3 years ago
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