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tatyana61 [14]
3 years ago
14

Help with this question please

Physics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

Your answer for this question would be AMU.

Explanation:

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Ann [662]

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he can explore other types of physical activity

Explanation:

lifting weights and paddling will help but running could also help

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An electric fan is set on its HIGH setting. After the Low push button is depressed, the angular speed of the fan blades decrease
brilliants [131]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

<span>a=Δω/Δt
</span><span>a=2π*Δf/Δt
</span><span>a=2π*(f2-f1)/Δt
</span>
<span>f1=f2-a*Δt/2π
</span><span>f2=800/60 rev/sec
</span><span>a=-42 rad/sec^2
</span><span>Δt=1.75sec
</span><span>so f1=25 rev/sec
 f1=1500 rev/min</span>
8 0
3 years ago
Which type of current flows inside the flashlight A direct B alternating C repeating D pulsating
anzhelika [568]

The flashlight is powered by one or more batteries.
Batteries supply Direct current (DC) .

7 0
3 years ago
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A bowling ball encounters a 0.760 m vertical rise on the way back to the ball rack. Ignore frictional losses and assume the mass
Gre4nikov [31]

To solve this exercise we need the concept of Kinetic Energy and its respective change: Initial and final kinetic energy.

Let's start considering that the angular velocity is given by,

\omega = \frac{v}{R}

Where,

V = linear speed

R = the radius

In the case of the initial kinetic energy:

KE_i=\frac{1}{2} mv^2 + \frac{1}{2}I \omega^2

Where I is the moment of inertia previously defined.

KE_i = \frac{1}{2}(m)3.5^2 + \frac{1}{2}* (\frac{2}{5} m R^2) (\frac{3.5}{R})^2

In the case of the final kinetic energy, we have to,

KE_f= mgh+ \frac{1}{2} mv^2 + \frac{1}{2} I \omega^2

KE_f = m * 9.81 * 0.76 + \frac{1}{2} m v^2 + \frac{1}{2} (\frac{2}{5} m R^2) (\frac{v}{R})^2

For conservation of Energy we have, that

KE_f = KE_i, then (canceling the mass and the radius)

\frac{1}{2} 3.5^2 + \frac{1}{2}(\frac{2}{5})(3.5)^2= 9.81 * 0.76 + \frac{1}{2} v^2 + \frac{1}{2} (\frac{2}{5}) (v)^2

8.575= 7.4556+ \frac{1}{2} v^2 + \frac{1}{2} (\frac{2}{5}) (v)^2

1.1194= \frac{1}{2}( v^2 + (\frac{2}{5}) (v)^2)

2.2388= (\frac{7}{5}) (v)^2

v=1.26m/s

7 0
4 years ago
How does a laser work?
a_sh-v [17]

Answer:

A laser is created when the electrons in atoms in special glasses, crystals, or gases absorb energy from an electrical current or another laser and become “excited.” The excited electrons move from a lower-energy orbit to a higher-energy orbit around the atom's nucleus.

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