Question 3 An molecule adsorbed at one site on a surface. An oxygen molecule is adsorbed onto a small patch of the surface of a
1 answer:
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Answer:
0.6m/s²
Explanation:
Given parameters:
Initial velocity = 3m/s
Final velocity = 4.5m/s
Time taken = 2.4s
Unknown:
Average acceleration = ?
Solution:
To solve this problem, we use the expression:
Acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
Acceleration = = 0.6m/s²
The work done by Nick as he raises the given mass over the given distance is approximately 2 Joules.
Given the data in the question:
- Mass raised;
- Distance covered;
Work done;
First we calculate the force used to raise the mass to the given distance.
Since the movement was vertical, the force must over come the mass and the pull of gravity ( ).
Using Newton's second law of Motion;
We substitute our values into the equation
Now, we determine the work done by Nick.
Work done is simply the energy transferred from one store to another.
It is expressed as;
So we substitute our values into the equation
Therefore, the work done by Nick as he raises the given mass over the given distance is approximately 2 Joules.
Learn more about Newton's law of motion: brainly.com/question/20066791
Answer:
Explanation:
The solution of the question cab e found in attachment below:
