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Tasya [4]
3 years ago
12

In a rate law, the rate constant, k, depends on which condition

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0
In a rate law, the rate constant, k, depends only on the temperature.

If the temperature is constant, the rate constant is a constant.
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Jennifer is learning the parts of the cell and knows that there must be a structure responsible for maintaining the homeostasis
Tatiana [17]
The answer will be the cell membrane
8 0
3 years ago
An unknown metal sample has a mass : of 11.29. and a volume of 2 cm3. What is the : density of the unknown metal? ​
tatuchka [14]

Answer:

\boxed{\sf Density \ of \ the \ unknown \ metal = 5.645 \ g/cm^3}

Given:

Mass = 11.29 g

Volume = 2 cm³

To Find:

Density of unknown metal

Explanation:

Formula:

\boxed{ \bold{Density = \frac{Mass}{Volume}}}

Substituting value of mass & volume in the formula:

\sf \implies Density =  \frac{11.29}{2} \\  \\   \sf \implies Density =  5.645 \: g/cm^3

3 0
3 years ago
Which statement is true of the particles that make up a substance?
Ket [755]

Answer: particle in gas have more energy than the particles in a liquid

<h3 />

Explanation: this is because the amount of energy is directly proportional to how random the system is. gaseous molecules are in a more constant random motion than the liquid molecules

5 0
3 years ago
How many hydrogen atoms are missing in ethane compared to ethane
Lera25 [3.4K]

Isomer types. The connectivity and molecular motion due to bond rotations within a molecule can result in atoms that are considered to be equivalent or non-equivalent types. For example, the six hydrogen atoms in ethane are considered to be chemically equivalent

6 0
3 years ago
Magnesium Oxide decomposes to produce 3.54 grams of oxygen gas. How many grams of magnesium oxide decomposed?
sukhopar [10]
<h2>Let us solve for it </h2>

Explanation:

Magnesium oxide

  • It is MgO  
  • Its molecular mass is : 24 +16=40 g
  • When MgO decomposes it forms = 3.54 g of oxygen gas  
  • when 40 g of MgO decomposes it forms = 16g of oxygen  
  • or we can say that :
  • 16g of oxygen is produced when 40 g of MgO is decomposed .
  • 1g of oxygen will be formed from =40/16g of MgO  
  • 3.54 g of oxygen will be formed = 40/16 x 3.54 =8.85g of MgO  

4 0
3 years ago
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