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3 years ago

If the sum of the external forces on an object is zero, then the sum of the external torques on it

Physics

1 answer:

Zarrin [17]3 years ago

5 0

Answer:

True.

Explanation:

If the sum of the external forces on an object is zero, then the sum of the external torques on it must also be zero.

The net external force and the net external torque acting on the object have to be zero for an object to be in mechanical equilibrium.

Hence, the given statement is true.

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What happens as water evaporates from a lake

NARA [144]

Answer:

As that liquid water is further heated, it evaporates and becomes a gas—water vapor. So C... Need branliest pls

Explanation:

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3 years ago

A 24 liter tank contains ideal helium gas at 27 degrees C anda pressure of 22 atm. How many moles of gas are in the tank?

frozen [14]

Answer:

d)21.5 moles

Explanation:

Given that

L = 24 L

T = 27 °C = 300 K

P = 22 atm

We know that ideal gas equation

P V = n R T

P=Pressure ,V= Volume ,n=Moles ,R=Universal gas constant ,T=Temperature

Now by putting the values

22 x 24 = n x 0.08206 x 300

n= 21.447 moles

n= 21.5 moles

Therefore the number of moles will be 21.5 moles.

The answer is "d".

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3 years ago

At the Indianapolis 500, you can measure the speed of cars just by listening to the difference in pitch of the engine noise betw

allsm [11]

To develop this problem it is necessary to apply the concepts related to the Dopler effect.

The equation is defined by

$f_i = f_0 \frac{c}{c+v}$

Where

$f_h$ = Approaching velocities

$f_i$ = Receding velocities

c = Speed of sound

v = Emitter speed

And

$f_h = f_0 \frac{c}{c+v}$

Therefore using the values given we can find the velocity through,

$\frac{f_h}{f_0}=\frac{c-v}{c+v}$

$v = c(\frac{f_h-f_i}{f_h+f_i})$

Assuming the ratio above, we can use any f_h and f_i with the ratio 2.4 to 1

$v = 353(\frac{2.4-1}{2.4+1})$

$v = 145.35m/s$

Therefore the cars goes to 145.3m/s

7 0

3 years ago

Chapter 36, Problem 007 Light of wavelength 586 nm is incident on a narrow slit. The angle between the first diffraction minimum

svp [43]

Answer:

$d =4.77\times 10^{-5}\ m$

Explanation:

given

wavelength of light λ = 479 nm

= 479 x 10⁻⁹ m

the angle

θ = 1.15 / 2 = 0.575°

using

condition for diffraction minimum ,

d sinθ = m λ

for first minimum m = 1

d sinθ = λ

therefore ,

slit width

$d =\dfrac{\lambda}{sin\theta}$

$d =\dfrac{479\times 10^{-9}}{sin 0.575^0}$

$d =\dfrac{479\times 10^{-9}}{0.01}$

$d =4.77\times 10^{-5}\ m$

hence, the width of the slit is equal to $d =4.77\times 10^{-5}\ m$

3 0

3 years ago

Preschool girls and boys do not differ in the amount of muscle they have<br> 1) True<br> 2) False

Marina86 [1]

Explanation:

False...............

3 0

3 years ago