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denis-greek [22]
3 years ago
12

Rank the following five elements by ionization energy Rank from highest to lowest ionization energy. To rank items as equivalent

, overlap themHighest LowestS, Cl, Si, Mg, Na
Chemistry
1 answer:
yan [13]3 years ago
7 0

Answer:

Cl

Si

Mg

Na

Explanation:

Ionization energy is the energy required to remove an electron from the valence shell of an atom to form an ion. Since metal are natural givers, they help people. Non metals are receivers hence it would be very hard for them to release their electrons.

For our arrangement, the key is that the ionization energy is expected to increase across the period to a maximum that terminates at the halogens. This is the more reason why halogens have the highest ionization energy and the alkali metals have the lowest.

Hence, from the options in the question, we can see that chlorine would have the highest because it is an halogen in group 17. Also expected is the fact that the ionization energy of that Mg is greater than that if Na. This is because Mg comes after Na in the same period and is thus expected to have higher ionization energy than Na

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^{85}_{37}Rb has 37 electrons in the orbit about its nucleus.

<h3>How to write an atomic symbol with atomic mass and atomic number?</h3>

Atomic mass is the total number of neutrons and protons present in the nucleus of an element.

The atomic number is the total number of protons present in the nucleus of an element.

For writing an atomic symbol, atomic mass is written on the top left of the atomic symbol, and the atomic number is written on the downside of the left of the symbol.

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An electrically neutral atom is an atom that has an equal number of electrons as well as protons.

Thus from the above conclusion we can say that  ^{85}_{37}Rb has 37 electrons.

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⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣧⣀⣀⣾⣿⣿⣿⣿

⣿⣿⣿⣿⣿⡏⠉⠛⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⣿

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Explanation:

3 0
3 years ago
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