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3 years ago

Which class includes an unsaturated hydrocarbon with a ring structure?

Chemistry

2 answers:

Troyanec [42]3 years ago

5 0

Answer:

The correct answer is aromatic hydrocarbons.

Explanation:

Aromatic compounds are named on the basis of their fragrant characteristics and are unsaturated hydrocarbon ring compositions, which demonstrate unique characteristics, comprising unusual stability because of their aromaticity.

They are usually signified as resonance compositions comprising double and single bonds. However, the bonding is more robust in comparison to a conjugated structure, and it is more precisely signified as delocalized electron density shared among all the atoms in the ring.

Tpy6a [65]3 years ago

3 0

Unsaturated hydrocarbons with ring structures are most likely belong to the class of aromatic hydrocarbons. In addition, this specific kind of hydrocarbons mostly has benzene in their molecular structures wherein its base formula would be C6H6 and they were first described by Pauling.

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In molecules, energy is stored in? Atoms Electrons The Nucleus Bonds

Nikolay [14]

Answer:

Atoms

Explanation:

Energy, potential energy, is stored in the covalent bonds holding atoms together in the form of molecules. This is often called chemical energy.

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3 years ago

Which of the following contains plasma?

UNO [17]

Answer:

It is mostly water (up to 95% by volume), and contains dissolved proteins (6–8%) (e.g. serum albumins, globulins, and fibrinogen), glucose, clotting factors, electrolytes (Na+, Ca2+, Mg2+, HCO3−, Cl−, etc.), hormones, carbon dioxide (plasma being the main medium for excretory product transportation) and oxygen.

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3 years ago

Read 2 more answers

Relationship between the variables of Pressure and Temperature of a gas?

pychu [463]

Answer:

The pressure of a given amount of gas is directly proportional to iys absolute temperature provided that that the volume does not change

7 0

3 years ago

How many grams of O2 are present in 44.1 L of O2 at STP?

ycow [4]

Taking into accoun the STP conditions and the ideal gas law, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

First of all, the STP conditions refer to the standard temperature and pressure, where the values used are: pressure at 1 atmosphere and temperature at 0°C. These values are reference values for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

P is the gas pressure.
V is the volume that occupies.
T is its temperature.
R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
n is the number of moles of the gas.

Then, in this case:

P= 1 atm
V= 44.1 L
n= ?
R= 0.082 $\frac{atmL}{molK}$
T= 0°C =273 K

Replacing in the expression for the ideal gas law:

1 atm× 44.1 L= n× 0.082 $\frac{atmL}{molK}$ × 273 K

Solving:

$n=\frac{1 atm x44.1 L}{0.082\frac{atmL}{molK}x273K}$

n=1.97 moles

Being the molar mass of O₂, that is, the mass of one mole of the compound, 32 g/mole, the amount of mass that 1.97 moles contains can be calculated as:

$1.97 molesx\frac{32 g}{1 mole}$ = 63.04 g ≈ 63 g

Finally, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

Learn more about the ideal gas law:

brainly.com/question/4147359?referrer=searchResults

7 0

3 years ago

How many grams of carbon are present in 45.0 g of CCl4?

lisabon 2012 [21]

To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:

45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present

Hope this answers the question. Have a nice day.

5 0

4 years ago