Explanation:
2,4-DNP is negative: aldehyde and ketone absent
Chromic acid is negative: alcohol absent.
KMnO4 test negative: alkene absent
The only positive result is for Fe(OH)2.
Nitro group-containing compounds react with ferrous hydroxide to give amine and ferric hydroxide red ppt. Hence given compound contains the nitro group (-NO2).
Answer : The work done on the surroundings is, 709.1 Joules.
Explanation :
The formula used for isothermally irreversible expansion is :

where,
w = work done
= external pressure = 1.00 atm
= initial volume of gas = 1.00 L
= final volume of gas = 8.00 L
Now put all the given values in the above formula, we get :



The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.
Therefore, the work done on the surroundings is, 709.1 Joules.
Answer
Ultraviolet
Explanation
The types of radiation and their wavelength are:
Gamma < 10⁻¹² m
X-rays 1 nm - 1 pm
Ultraviolet 400 nm - 1 nm
Visible 750 nm - 400 nm
Near-infrared 2.5 μm - 750 nm
Infrared 25 μm - 2.5 μm
Microwaves 1 mm - 25 μm
Radio waves > 1 mm
Hence, the given wavelength of 2.86 X 10⁻⁸ m corresponds to Ultraviolet.
Answer:
C Rate ![=k [A]^{2} [B][C]^{-1}](https://tex.z-dn.net/?f=%3Dk%20%5BA%5D%5E%7B2%7D%20%5BB%5D%5BC%5D%5E%7B-1%7D)
Explanation:
In order to determine the correct rate law, let's use Trial 1 as baseline. Therefore:
An increase in [A] in Trial 2 by a factor of
leads to an increase in the rate of reaction by a factor of 2 (i.e. the reaction rate is doubled). Thus, there is second order in [A].
Similarly,
An increase in [B] in Trial 3 by a factor of 1.667 leads to an increase in the rate of reaction by a factor of 1.667. Thus, there is first order in [B].
Futhermore,
An increase in [C] in Trial 4 by a factor of 1.71 leads to a decrease in the rate of reaction by 1.71. Thus, there is inverse first order in [C].
Therefore, the correct rate law is:
Rate ![=k [A]^{2} [B][C]^{-1}](https://tex.z-dn.net/?f=%3Dk%20%5BA%5D%5E%7B2%7D%20%5BB%5D%5BC%5D%5E%7B-1%7D)
Al203 is the formula for aluminum oxide