Answer:
Part A: 2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B: -r = K*[N₂O]²
Part C: K= k1*k2
Explanation:
Part A
To do the balance chemical question for the overall chemical reaction, we must sum the reaction of the steps, eliminating the intermediaries, which are the compounds that have the same amount both at reactants and products (bolded).
N₂O(g) ⇄ N₂(g) + O(g)
N₂O(g) + O(g) ⇄ N₂(g) + O₂(g)
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2N₂O(g) + O(g) ⇄ 2N₂(g) + O(g) + O₂(g)
2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B
The velocity of the reaction (r) can be calculated based on the reactants or based on the products. Let's do it based on the disappearing of the reactant. Because it is disappearing, the variation at its concentration must be negative, so the rate will be negative.
Let's suppose its an elementary reaction, so, the concentration of the reactant must be elevated by its coefficient. And let's call the overall rate constant as K:
-r = K*[N₂O]²
Part C
Because the steps were summed, and the reactions were not multiplied by a constant or inverted, the constant K is just the multiplication of the constants of the steps:
K= k1*k2
Explanation:
the answer is true because I had this question and got it right
Answer:
85.8 g
Explanation:
The molar mass of BaCl₂ is 208.233 g/mol, so 210.1 g is about ...
210.1/208.233 ≈ 1.009 mol
The molar mass of K is about 39.089 g/mol, so 45 g is about ...
45/39.089 ≈ 1.1509 mol
The balanced equation seems to be ...
BaCl₂ + 2K ↔ 2KCl + Ba
This reaction requires 2 moles of potassium for each mole of barium chloride, so the available potassium limits the reaction. The result is as many moles of potassium chloride as there are moles of potassium.
The 1.1509 moles of KCl, at 74.551 g/mol will have a mass of about 85.8 g.
The reaction produces 85.8 g of KCl.
Answer:
Final temperature = 28.0 degrees C.
Explanation:
heat absorbed = mass * specific heat * rise in temperature.
The specific heat of water is 4.186 J /g/C so we have the equation
209 = 10 * 4.186 * x where x is the temperature increase
41.86x = 209
= 5 degrees C.
Answer:
B. 4 Fe + 3 0₂---> 2 Fe₂O3
Explanation:
(A) Ir + O₂--> IrO₂ No: Ir is iridium
(B) 4 Fe + 3 0₂---> 2 Fe₂O3 Yes: Fe is iron and O is oxygen, and the equation is balanced.
(C) I+ 0₂ ---> 10₂ No: I is iodine
(D) 3 Ir + 0₂ -> 6 Ir₂03 No: I is iodine
