Ask question

Ask question

All categories

3 years ago

6

Will give BRAINLIEST!!!!!!

2 answers:

ankoles [38]3 years ago

8 0

Answer:

N:ki n:kn:kNN

Step-by-step explanation:

VladimirAG [237]3 years ago

7 0

Answer:

Remember the maximum height will be at the vertex. The x value of the vertex is your time, so use x=-b/2a. Then if it had also asked what the height was, you would plug that answer into your equation to find the y value of the vertex. Pretty sure your teacher is just asking you to find the x though:)

Step-by-step explanation:

You might be interested in

How do you find the volume of a shape with 2 different heights and 1 extra block on the width??

shusha [124]

Question unclear

Step-by-step explanation:

If it is a trapezoid, you can simply find the average of the two base lengths, but I can't help much without seeing the shape. Please add a picture of the shape.

6 0

3 years ago

Read 2 more answers

Does anyone know the answer?

allsm [11]

D. Points on a line do not have a quadrant.

5 0

3 years ago

Read 2 more answers

find four consecutive even integers such that the sum of the third and fourth is 6 less than four times the first

lisabon 2012 [21]

Answer:

The numbers are 2, 4, 6 and 8

Step-by-step explanation:

let the four numbers be x, y, z and l respectively

then:

x+y+z+l

(z+l)–6=4x

since they are all four consecutive even integers

then y=x+2

z=y+2=x+4

l=z+2=x+6

since (z+l)–6=4x

then ((x+4)+(x+6))–6=4x

2x+4=4x

4=4x–2x

4=2x

2=x

5 0

3 years ago

Which statement represents the expression 200 + (-200)?

Tems11 [23]

Answer:

The Answer is 0 or D:)

Step-by-step explanation:

100+(-200)=0

5 0

3 years ago

A force of 8 N makes an angle of π/4 radian with the y-axis, pointing to the right. The force acts against the movement of an ob

Grace [21]

Answer:

a) F= 4 $\sqrt{2}$ i + 4 $\sqrt{2}$ j

b) Θ=11.3

c) The work done is 20 $\sqrt{2}$

Step-by-step explanation:

a) ||F||=8, α=π/4

Fx=||F||·sin(π/4)=8· $\frac{\sqrt{2}}{2}$

Fy=||F||·cos(π/4)=8· $\frac{\sqrt{2}}{2}$

F=Fx i + Fy j = 4 $\sqrt{2}$ i + 4 $\sqrt{2}$ j

b) We can find the value of Θ using the equation:

cos(Θ)= $\frac{F.D}{||F||||D||}$

where:

D= 3 i + 2 j

F=4 $\sqrt{2}$ i + 4 $\sqrt{2}$ j

The dot product is defined as the sum of the products of the components of each vector as:

F · D= $(4\sqrt{2})*3+(4\sqrt{2})*2=20\sqrt{2}$

||F||= 8

||D||= $\sqrt{3^2+2^2} =\sqrt{13}$

Hence:

Θ=arccos( $\frac{20\sqrt{2} }{8\sqrt{13} }$ )

Θ=arccos(0.981)

Θ= 11.3°

c) Work is equal to:

F · D= $(4\sqrt{2})*3+(4\sqrt{2})*2=20\sqrt{2}$ =28.3

Other way of obtainig the work is:

||F||||D||cos(Θ)

where:

||F||= 8

||D||= $\sqrt{3^2+2^2} =\sqrt{13}$

Θ=11.3°

So, ||F||||D||cos(Θ)=8× $\sqrt{13}$ ×cos(11.3°)=28.3

3 0

3 years ago