It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:

Step-by-step explanation:




Answer:
The amount that we should deposit in each bank is around $942.
Step-by-step explanation:
Case 1:
A=$1000
n = 12
t = 2
r = 3% or 0.03
p = ?
The compound interest formula is :

Substituting values in the formula;

=> 
=> 

p = $941.84
Case 2:
A=$1000
n = 365
t = 2
r = 3% or 0.03
p = ?

=> 
=>

p = $941.76
The amount that we should deposit in each bank is around $942.