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3 years ago

15

5-2(m-3)=1 can y’all help me this is hard

1 answer:

Naddik [55]3 years ago

3 0

Answer:

m = 5

Step-by-step explanation:

5 - 2 * (m - 3) = 1

5 - 2m + 6 = 1

-2m + 11 = 1

-2m = -10

2m = 10

m = 5

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Send help please!! i want to complete it asap

Nadusha1986 [10]

It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
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2 years ago

Can someone help me x^2 + 3 - 6(3x + 4) i will give brainliest

dangina [55]

Answer:

${x}^{2} - 18x - 21$

Step-by-step explanation:

${x}^{2} + 3 - 6(3x + 4)$

${x}^{2} + 3 - 18x - 24$

${x}^{2} - 21 - 18x$

$\boxed{\green{= {x}^{2} - 18x - 21}}$

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2 years ago

Derek estimated the cost of his grocery bill to be $75, but it actually cost $110. Find the percent error rounded to the nearest

UkoKoshka [18]

I could be wrong, but I think its 35%.

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2 years ago

The Monthly Bank pays 3 percent interest, compounded monthly, on their savings accounts. The Daily Bank pays 3 percent interest,

Novosadov [1.4K]

Answer:

The amount that we should deposit in each bank is around $942.

Step-by-step explanation:

Case 1:

A=$1000

n = 12

t = 2

r = 3% or 0.03

p = ?

The compound interest formula is :

$A=p(1+\frac{r}{n})^{nt}$

Substituting values in the formula;

$1000=p(1+\frac{0.03}{12})^{12\times2}$

=> $1000=p(1.0025)^{24}$

=> $1000=1.06175p$

$p=\frac{1000}{1.06175}$

p = $941.84

Case 2:

A=$1000

n = 365

t = 2

r = 3% or 0.03

p = ?

$1000=p(1+\frac{0.03}{365})^{365\times2}$

=> $1000=p(1.0000822)^{730}$

=> $1000=1.06184p$

$p=\frac{1000}{1.06184}$

p = $941.76

The amount that we should deposit in each bank is around $942.

5 0

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