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Law Incorporation [45]

3 years ago

5

Which is a substance fruit salad granola cereal spaghetti or table salt

2 answers:

sweet-ann [11.9K]3 years ago

5 0

Table salt is a substance

Fofino [41]3 years ago

3 0

Table salt. It is a specific molecule: NaCl. All of those other food items have way too many kinds of molecules in them to be called a substance.

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Which of the following is an example of a biological polymer?

katrin2010 [14]

A) polyester, hope it was quick enough

4 0

3 years ago

As you move from left to right across a period, what happens to the atomic radil?

egoroff_w [7]

Answer:

Moving Across a Period

Moving from left to right across a period, the atomic radius decreases. The nucleus of the atom gains protons moving from left to right, increasing the positive charge of the nucleus and increasing the attractive force of the nucleus upon the electrons

4 0

4 years ago

How many molecules of nitrogen gas are in 15 L of nitrogen gas

uranmaximum [27]

Answer:

$3.98\times 10^{23}$

Explanation:

Since we have $N_A$ number of molecules in 22.4 L, in 15 L we have:

$\frac{15}{22.4}\times 6.023 \times 10^{23}$ molecules.

5 0

3 years ago

What properties do atoms of the same element share? Select all that apply.

Tcecarenko [31]

I believe A is you’re answer

6 0

3 years ago

Read 2 more answers

A possible mechanism for the overall reaction Br2 (g) + 2NO (g) → 2NOBr (g) is NO (g) + Br2 (g) rightwards arrow with k space 1

omeli [17]

Answer : The rate law for formation of NOBr based on this mechanism is, $\frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2$

Explanation :

The overall reaction is:

$Br_2(g)+2NO(g)\rightleftharpoons 2NOBr(g)$

Rate law = $k[Br_2][NO]^2$

The first step of the overall reaction is:

$NO(g)+Br_2(g)\overset{k_1}{\rightarrow} NOBr_2(g)$

$NO(g)+Br_2(g)\overset{k_1^-}{\leftarrow} NOBr_2(g)$

Rate law 1 = $k_1[Br_2][NO]$

Rate law 2 = $k_1^-[NOBr_2]$

The second step of the overall reaction is:

$NOBr_2(g)+NO(g)\overset{k_2}{\rightarrow} 2NOBr$

Rate law 3 = $k_2[NOBr_2][NO]$

Now rate law of overall reaction can be obtained as follows.

We are multiplying rate law 1 and rate law 3 and dividing by rate law 2, we get:

Rate law = $\frac{[k_1[Br_2][NO]]\times [k_2[NOBr_2][NO]]}{[k_1^-[NOBr_2]]}$

Rate law = $\frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2$

Rate law = $k[Br_2][NO]^2$

The rate law for formation of NOBr based on this mechanism is, $\frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2$

4 0

3 years ago