<u>Answer:</u>
The velocity of the bus be is 0 miles/second
<u>Explanation:</u>
Given, a bus travelled a distance of 20 miles north and 20 miles back to the starting point
Hence, total distance = 20 + 20 = 40 miles
Velocity is calculated by the formula:
Velocity = ![\frac{\text { Displacement }}{\text { Time }}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7B%20Displacement%20%7D%7D%7B%5Ctext%20%7B%20Time%20%7D%7D)
Displacement = ![20+(-20)=0 \text { miles }](https://tex.z-dn.net/?f=20%2B%28-20%29%3D0%20%5Ctext%20%7B%20miles%20%7D)
Velocity = ![\frac{0}{T i m e}=0 \text { miles/second }](https://tex.z-dn.net/?f=%5Cfrac%7B0%7D%7BT%20i%20m%20e%7D%3D0%20%5Ctext%20%7B%20miles%2Fsecond%20%7D)
Therefore, the velocity of the bus is 0 miles/second
It would be fatal for all.The ones on the side of sun would get everything but the ones farer than the sun wouldn't survive.There would be day forever on one side and night forever on other.
the blades in a windmill rotate
Answer:
\left \{ {{y=206} \atop {x=82}}Pb \right.
Explanation:
isotopes are various forms of same elements with different atomic number but different mass number.
Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are
- Alpha particle emission \left \{ {{y=4} \atop {x=2}}He \right.
- Beta particle emission \left \{ {{y=0} \atop {x=-1}}e \right.
- gamma radiation \left \{ {{y=0} \atop {x=0}}γ \right.
in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.
Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below
\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right + \left \{ {{y=0} \atop {x=0}}γ\right.
Thus the atomic symbol is \left \{ {{y=206} \atop {x=82}}Pb\right