First read the introduction.
Seconds look at the pictures how to build it.
The energy released in nuclear reactions are far larger than that released in chemical reactions due to the release of nuclear energy from the nucleus.
<h3>Why is the energy released in a reaction?</h3>
Energy is released in a reaction due to the breaking of bonds are well as formation of bonds.
The quantity of energy released in reactions differs according to the reaction type involved.
When compared to chemical reactions, the energy released in nuclear reactions are very much higher because of the changes that occurs in the nucleus of the atoms involving nuclear energy.
The energy, E released in nuclear reactions is given by the formula below:

where m is the mass of the substance and c is the speed of light.
Therefore, the energy released in nuclear reactions are far larger than that released in chemical reactions.
Learn more about nuclear reactions at: brainly.com/question/984564
Answer:
*2Kl+Pb(NO3)2=PbI2+2KNO3: double replacement.
*2Al+3CuSO4=Al2(SO4)3+3Cu: single replacement.
*C2H5OH+3O2=2CO2+3H2O: combustion.
Explanation:
Hello there!
In this case, according to the required, it turns out necessary for us to recall the five types of reactions, combination, decomposition, single and double replacement and combustion as shown on the attached figure.
In such a way, since the first reaction follows the pattern AB+CD-->AD+CB we infer it is double replacement; the second reaction follows the patter A+BC-->AC+B and therefore it is single replacement; and the last one follows the pattern of combustion reaction due to the presence of CO2 and H2O on the products side.
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Answer:
A
Explanation:
compare it to carbon 12 I believe
Answer:
Molecular formula of cyanogen is C₂N₂
Explanation:
We apply the ideal gases law to find out the mole of cyanogen
P . V = n. R. T
Firstly let's convert the pressure in atm, for R
750 mmHg = 0.986 atm
25°C + 273 = 298K
0.986 atm . 0.714L = n . 0.082 L.atm/mol.K .298K
(0.986 atm . 0.714L) / (0.082 L.atm/mol.K .298K) = n
0.0288 mol = n
Molar mass of cyanogen = mass / mol
1.50 g /0.0288 mol = 52.02 g/m
Let's apply the percent, to know the quantity of atoms
100 g of compound contain 46.2 g of C and 53.8 g of N
52.02 g of compound contain:
(52.02 . 46.2) / 100 = 24 g → 2 atoms of C
(52.02 . 53.8) / 100 = .28 g → 2 atoms of N