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Ronch [10]
3 years ago
10

How to calculate the mass percent of hydrogen

Chemistry
1 answer:
Keith_Richards [23]3 years ago
8 0

Answer:

divide the mass of element in 1 mole of the compound by the compound's molar mass and multiply the answer by 100.

Explanation:

take the molar mass of hydrogen in the water molecule, divide by the total molar mass of water, and multiply by 100.

does it help?

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Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound?
kotykmax [81]

Answer : The correct option is, (C)  2.57\times 10^{24}

Solution for Part 1 : Given,

Mass of K_2S = 235 g

Molar mass of K_2S = 110.262 g/mole

First we have to calculate the moles of K_2S.

\text{Moles of }K_2S=\frac{\text{Mass of }K_2S}{\text{Molar mass of }K_2S}=\frac{235g}{110.262g/mole}=2.13moles

Now we have to calculate the number of atoms of potassium in the given compound.

In the given compound, there are 2 atoms of K and 1 atom of S.

As, 1 mole contains 2\times 6.022\times 10^{23} number of potassium atoms

So, 2.13 moles contains 2.13\times 2\times 6.022\times 10^{23}=2.57\times 10^{24} number of potassium atoms

Therefore, the number of potassium atoms in given compound is,  2.57\times 10^{24}

Explanation for Part 2 :

Statement 1 : A balloon shrinks when it's taken outside in the winter.

This statement follow the Charles's law. There is a direct relation between the temperature and volume. As the temperature decreases, the volume also decreases and vice-versa.

Statement 2 : A closed, flexible container expands when it's heated.

This statement follow the Charles's law. There is a direct relation between the temperature and volume. As the temperature increases, the volume also increases and vice-versa.

Statement 3 : When the size of an air chamber is increased, the air pressure decreases.

This statement follow the Boyle's law. There is an inverse relation between the pressure and volume. As the pressure decreases, the volume increases and vice-versa.

Statement 4 : Pressing on an inflated balloon decreases its size.

This statement follow the Boyle's law. There is an inverse relation between the pressure and volume. As the pressure increases, the volume decreases and vice-versa.

Statement 5 : A balloon expands when air is blown into it.

This statement follow the Avogadro's law. There is a direct relation between the number of moles of gas and volume. As the number of moles of air increases, the volume also increases and vice-versa.

5 0
4 years ago
Which of the following statements best describe the particles of a liquid?
Norma-Jean [14]

Answer:

you already have the right answer b

Explanation:

3 0
3 years ago
What happens when a metal is reduced. Give an example of a metal being reduced
AlexFokin [52]

Answer:

The oxidation number of the metal decreases

2 Al  + Fe₂O₃ → Al₂O₃ + 2 FeO

The metal element iron, is reduced from Fe⁺³ in Fe₂O₃ to Fe⁺² in FeO

Explanation:

When an element gains electron, the element becomes reduced, hence when a metal is reduced, the metal gains electrons, which reduces the oxidation number of the metal

An example of a metal being reduced is;

2 Al  + Fe₂O₃ → Al₂O₃ + 2 FeO

In the above reaction, the iron (III) oxide is reduced to iron (II) oxide by aluminium metal.

6 0
4 years ago
Question 1 (1 point)
andriy [413]

Answer:

The answer would be:

It becomes unstable.

7 0
3 years ago
Read 2 more answers
How many moles of H2s are produced when 2.25 moles Hcl react with excess zns
svlad2 [7]

Answer:

1.125 moles of H2S

Explanation:

From 2HCl(aq) + ZnS(s) ---------> H2S (g) + ZnCl2 (aq)

From the reaction equation;

2 moles of HCl produces 1 mole of H2S

Therefore 2.25 moles of HCl will produce 2.25 ×1/2 = 1.125 moles of H2S

Recall that it was explicitly stated in the question that ZnS is the reactant in excess. This implies that HCl is the limiting reactant and controls the amount of product obtained.

4 0
3 years ago
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