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Wittaler [7]
4 years ago
5

Why does the emission spectrum of hydrogen or unknown source have a distinct line spectrum instead of a continuous one?

Physics
1 answer:
aleksandr82 [10.1K]4 years ago
3 0

Answer

When an electron makes transition from a state of higher energy to a state of lower energy it does so by emitting energy in form of radiation in the visible spectrum of light.

Since the basic postulates of the atomic theory is that the energy that the electron possess in it's orbit's takes only discrete values and cannot take any random value thus when an electron makes a transition from a state of higher energy to state of lower energy it will emit radiation with energy equal to difference between the energy levels of the 2 orbit's thus we only observe discrete lines.

Mathematically when an electron makes a transition between states the wavelength of light it releases is given by

\frac{1}{\lambda }=R_{\infty }(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}})

where R_{\infty } is Rydberg constant

n_{1} is upper energy level

n_{2} is lower energy level

thus we can see that only discrete wavelength's are released and not continuous wavelength's of light.

You might be interested in
A chain reaction results when a uranium atom is struck by a/an ______________released by a nearby Uranium atom undergoing fissio
finlep [7]

Answer:

Chain reaction is possible by neutron

Explanation:

Nuclear reaction is mainly two types,

⇒ Nuclear Fission : heavy atom split into two light atom.

Ex. Uranium, thorium

⇒ Nuclear fusion : lighter atom combine together

Ex. Hydrogen to helium

In fusion reaction the large amount of energy is produced as compare to fission reaction.

Sun gets brighter by fusion reaction.

In case of uranium fission reaction is possible by colliding neutron.

8 0
4 years ago
How do I do number 8, plz respond quick, I have a big unit test on this and I’m rocking a 65 science average rn. Thank you for t
xxTIMURxx [149]

Answer:

3 is the correct answer for number 8

6 0
4 years ago
Read 2 more answers
If 200 ml of tea at 90 °C is poured into a 400 g glass cup initially at 25 °C, what would be the final temperature of the mixtur
sweet-ann [11.9K]

The final temperature of the mixture is 43.62 °C

To solve the question above, we apply the law of calorimetry

The law of calorimetry: which states that if there is no lost of heat the surrounding, heat lost is equal to heat gained, or it can be stated as heat absorbed by a cold body is equal to heat released by a hot body, provided there is no lost of heat to the surrounding.

The law above is expressed mathematically as

Cm(t₁-t₃) = C'm'(t₃-t₂)............. Equation 1

Using equation 1 to solve the question,

Let: C = specific heat capacity of glass cup, m = mass of glass cup, C' = specific heat capacity of tea, m' = mass of tea, t₁ = initial temperature of tea, t₂ = initial temperature of glass cup, t₃ = final temperature of the mixture.

From the question,

Given: m = 400 g = 0.4 kg, C = 840 J/kg°C, m' = 200g (tea is a liquid made of water and the volume of water in ml is thesame a its mass in gram) = 0.2 kg, C' = 4186 J/kg.°C, t₁ = 90°C, t₂ = 25°C

Substitute these values into equation 1 and solve for t₃

0.4(840)(90-t₃) = 0.2(4186)(t₃-25)

336(90-t₃) = 837.2(t₃-25)

30240-336t₃ = 837.2t₃-20930

collect like terms

837.2t₃+336t₃ = 30240+20930

  1173.2t₃ = 51170

t₃ = 51170/1173.2

t₃ = 43.62 °C

Hence, the final temperature of the mixture is 43.62 °C

7 0
3 years ago
Read 2 more answers
A diode has a power rating of 5W. If the diode voltage is 3.6V and the diode current is 1.75A, what is the power dissipation?​
son4ous [18]

Answer:

Explanation:

Power = current * voltage

Power = 3.6 * 1.75

Power = 6.3 watts.

I hope this diode does not have to do this for very long. The power dissipation is above the diode's rated power -- a condition that won't last forever.

The power dissipation is 6.3 watts.

4 0
3 years ago
A power plant generates 150 MW of electrical power. It uses a supply of 1000 MW from a geothermal source and rejects energy to t
marissa [1.9K]

Answer:

- the power to the air is 850 MW

- mass flow rate of the air is 84577.11 kg/s

Explanation:

Given the data in the question;

Net power generated; W_{net = 150 MW

Heat input; Q_k = 1000 MW

Power to air = ?

For closed cycles

Power to air Q₀ = Heat input; Q_k - Net power generated; W_{net

we substitute

Power to air Q₀  = 1000 - 150

Q₀ = 850 MW

Therefore,  the power to the air is 850 MW

given that ΔT = 10 °C

mass flow rate of air required will be;

⇒ Q₀ / CpΔT

we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K

we substitute

⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]

⇒ ( 850 × 10³ ) / 10.05

⇒ 84577.11 kg/s

Therefore, mass flow rate of the air is 84577.11 kg/s

3 0
3 years ago
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