Answer:
-5.8868501529 m/s² or -5.8868501529g
0.118909090909 s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Dividing by g
The acceleration is -5.8868501529 m/s² or -5.8868501529g
The time taken is 0.118909090909 s
Fresh snow is the surface that exhibits the highest albedo measurement.
It takes twice the force to produce the same acceleration in the 2kg rock.
Answer:
false im just trying to get it if you'd like to give it to me
Let be the average acceleration over the first 2.46 seconds, and the average acceleration over the next 6.79 seconds.
At the start, the car has velocity 30.0 m/s, and at the end of the total 9.25 second interval it has velocity 15.2 m/s. Let be the velocity of the car after the first 2.46 seconds.
By definition of average acceleration, we have
and we're also told that
(or possibly the other way around; I'll consider that case later). We can solve for in the ratio equation and substitute it into the first average acceleration equation, and in turn we end up with an equation independent of the accelerations:
Now we can solve for . We find that
In the case that the ratio of accelerations is actually
we would instead have
in which case we would get a velocity of