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Kruka [31]
3 years ago
11

What happens when someone is walking across the carpeted room then touches a metal door knob

Physics
1 answer:
igomit [66]3 years ago
6 0
Static electricity travels to the door knob because of the friction caused by the feet on the carpet. the friction traveled through the person, to their hand, and to the door knob because it is the best conductor.
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An automobile engine delivers 47.4 hp. how much time will it take for the engine to do 6.82 × 105 j of work? one horsepower is e
kogti [31]
1 horsepower is equal to 746 W, so the power of the engine is
P=47.4 hp \cdot 746  \frac{W}{hp}=35360 W
The power is also defined as the energy E per unit of time t:
P= \frac{E}{t}
Where the energy corresponds to the work done by the engine, which is E=6.82 \cdot 10^5 J. Re-arranging the formula, we can calculate the time t needed to do this amount of work:
t =  \frac{E}{P}= \frac{6.82 \cdot 10^5 J}{35360 W}=19.3 s
8 0
3 years ago
What is a primitive solid?
otez555 [7]

Answer:

A primitive solid is a 'building block' that you can use to work with in 3D. Rather than extruding or revolving an object, AutoCAD has some basic 3D shape commands at your disposal.

Explanation:

4 0
3 years ago
Can you please help quick
Mademuasel [1]

Answer:

1. the difference between a series circuit and parallel are if a bulb goes out in a series circuit all go out and in a parallel if one goes out all the others stay on.

2. the function of a switch is to determine if the circuit is closed or open and how is stays on.

Explanation:

5 0
3 years ago
Read 2 more answers
How long in seconds will it take a car traveling at 100 miles/hour to travel the length of an American Football field?
Mrrafil [7]

Answer:

It will take 2.45 seconds.

Explanation:

A football field measured 120 yards, that is arround 0.068 miles, the car is moving with a constant speed so the formula we have to apply for this is:

t=\frac{x}{v}\\where\\x=distance\\v=speed\\

t=\frac{0.068}{100}\\t=0.00068hrs

in order to obtain the time in seconds:

tsec=0.00068hr*(\frac{3600sec}{1hr} )\\tsec=2.45 sec

6 0
3 years ago
A student stretches an elastic band by 0.8 m in 0.5 seconds. The spring constant of the elastic band is 40 N/m. What was the pow
miv72 [106K]

Answer:

The power exerted by the student is 51.2 W

Explanation:

Given;

extension of the elastic band, x = 0.8 m

time taken to stretch this distance, t = 0.5 seconds

the spring constant, k = 40 N/m

Apply Hook's law;

F = kx

where;

F is the force applied to the elastic band

k is the spring constant

x is the extension of the elastic band

F = 40 x 0.8

F = 32 N

The power exerted by the student is calculated as;

P = Fv

where;

F is the applied force

v is velocity = d/t

P = F x (d/t)

P = 32 x (0.8 /0.5)

P = 32 x 1.6

P = 51.2 W

Therefore, the power exerted by the student is 51.2 W

3 0
3 years ago
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