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Leto [7]
4 years ago
12

A car starts from rest and drives at 45 m/s in 20 s. how far did it travel

Physics
1 answer:
Schach [20]4 years ago
6 0

Answer:

distance=speed×time.

45×20=900m.

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If an object is travelling faster than its own sound waves, which of the following is created?
Andrej [43]

Answer:

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Explanation:

When an object travels faster than the speed of sound, a sonic boom is created. A ring of pressure waves (probably why wave destruction and pressure cooker are options lol) are created, which is why when you see a jet make a sonic boom there looks like a ring shaped cloud behind it. Hope this helps! For further confirmation/information, just look up sonic boom science (or else you will get sonic boom the video game)

7 0
3 years ago
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Show the molecular formula and electron structure of the simplest compound that forms with only carbon and hydrogen atoms.
zavuch27 [327]

The simplest compound of hydrocarbon is methane

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  • It belongs to alkane group and has single bonds.

The electron structure attached

3 0
2 years ago
What is electrical energy converted to inside a toaster?
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4 0
3 years ago
Particle 1 has mass 4.6 kg and is on the x-axis at x = 5.7 m. Particle 2 has mass 7.2 kg and is on the y-axis at y = 4.2 m. Part
Iteru [2.4K]

To solve this problem it is necessary to apply the concepts related to the Gravitational Force, for this purpose it is understood that the gravitational force is described as

F_g = \frac{Gm_1m_2}{r^2}

Where,

G = Gravitational Universal Force

m_i = Mass of each object

To solve this problem it is necessary to divide the gravitational force (x, y) into the required components and then use the tangent to find the angle generated between both components.

Our values are given as,

m_1 =4.6 kg\\m_2 = 7.2 kg\\m_3 = 2.6 kg\\r_1 = 5.7 m\\r_2 = 4.2 m

Applying the previous equation at X-Axis,

F_x = \frac{Gm_1m_3}{R_{1}^2}\\F_x = \frac{6.67*10^{-11}*4.6*2.6}{5.7^2}\\F_x = 2.46*10^{-11}N

Applying the previous equation at Y-Axis,

F_y = \frac{Gm_2m_3}{R_2^2}\\F_y = \frac{6.67*10^{-11}*7.2*2.6}{4.2^2}\\F_y = 7.08*10^{-11} N

Therefore the angle can be calculated as,

tan\theta = \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{7.08*10^{-11}}{2.46*10^{-11}}\\\theta = 71\°

Then in the measure contrary to the hands of the clock the Force in the particle 3 is in between the positive direction of the X and the negative direction of the Y at 71 ° from the positive x-axis.

5 0
4 years ago
The same 200 N force acts on an area greater than 2m2.<br> What happens to the pressure?
bixtya [17]

the pressure is (200 N)/(10 cm2)×(100 cm/M)2=200,000 pa

4 0
3 years ago
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