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4 years ago

7

When heat is added to a substance, describe how the molecules are affected. Use the words kinetic energy and potential energy ap

propriately?

1 answer:

shepuryov [24]4 years ago

3 0

When heat is added to a substance, the molecules increase kinetic energy. in other words, the particules speed up.

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A 0.110 kg cube of ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.70

Sonbull [250]

Answer:

the distance by which the height of the liquid in the cylinder change after the ice gets melted = 0.528 cm

Explanation:

The change in volume of glycerin when the ice cube is placed on the surface of the glycerin can be represented as:

$V = \frac{m}{ \rho}$

Given that ;

the mass of the ice cube (m) = 0.11 kg = 0.110 × 10³ g

density of the glycerine ( $\rho$ ) = 1.260 kg/L = 1.260 g/cm³

Then:

V = $\frac{0.110*10^3 \ g}{1.260 \ g/cm^3}$

V = $0.0873*10^3 \ cm^3 (\frac{1L}{10^3 cm^3})$

V = 0.0873 L

Now;Initially the volume of the glycerin before the ice cube starts to melt is:

$V_1 = V_i + V\\\\V_1 = V_i+ 0.0873 \ L$

However; the volume of the water produced by the 0.11 kg ice cube = $0.11*10^3 \ cm^3$

The expression for change in the volume of glycerin after the ice cube starts to melt is as follows:

$V_2 = V_i + V"$

replacing $V"$ with $0.11*10^3 \ cm^3$ ; we have:

$V_2 = V_i (0.11*10^3 \ cm^3 )(\frac{1 \ L }{10^3 \ cm^3})$

$V_2 = V_i + 0.11 \ L$

The overall total change in the volume of the glycerin is illustrated as:

$V_f = V_2 - V_1$

Now; from the foregoing ; lets replace the respective value of $V_2$ and $V_1$ in the above equation ; we have;

$V_f = (V_i + 0.11 \ L) - (V_i + \ 00873 \ L)\\ \\V_f = 0.11 L - 0.0873 \ L\\\\V_f = 0.0227 \ L$

The formula usually known to be the volume of a cylinder is :

$V = \pi r ^2 h$

For the question ; we will have:

$V_f = \pi r ^2 h$

making h the subject of the formula ; we have:

$h = \frac{V_f}{\pi r^2}$

replacing 0.0227 L for $V_f$ and the given value of radius which is = 3.70 cm; we have:

$h = \frac{0.0227 \ L ( \frac{10^3 \ cm^3}{1\ L})}{\pi * (3.70 cm)^2}$

$h = \frac{22.7 \ cm^3}{\pi * (3.70 cm)^2}\\\\h = 0.528 \ \ cm$

Thus ; the distance by which the height of the liquid in the cylinder change after the ice gets melted = 0.528 cm

8 0

4 years ago

The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.6 square inches. If a force of 5.6 lb

balu736 [363]

Answer:

16.8 lb is the force on the brake pad of one wheel.

Explanation:

Force applied on the piston = $F_1=5.6 lb$

Area of the piston = $A_1=0.6 inches^2$

Force applied on the brakes = $F_2$

Area of the brakes = $A_2=1.8 inches^2$

Applying Pascal's law: 'For an incompressible fluid pressure at one surface is equal to the pressure at other surface'.

$\frac{F_1}{A_2}=\frac{F_2}{A_2}$

$F_2=\frac{5.6 lb\times 1.8 inhes^2}{0.6 inches^2}=16.8 lb$

16.8 lb is the force on the brake pad of one wheel.

5 0

4 years ago

Compared with a force, a torque involves

ycow [4]

A rotational movement.

6 0

3 years ago

Im confused can someone explain what I have to do

Studentka2010 [4]

For numbers 1 and 3 it is giving you the answers i believe

number 1 would be 20 joules of potential energy on the far left and far right point

number 3 would the (3rd) point as it says it has 20 joules of kinetic energy

sorry if this doesn’t help

5 0

3 years ago

Two long straight wires enter a room through a window. One carries a current of 3.0 ???? into the room while the other carries a

Tju [1.3M]

Answer:

$\begin{equation}\\\oint_LB.dl\\\end{equation}$ = -8πx $10^{-7}$

Explanation:

If you need calculate

$\begin{equation}\\\oint_L B.dl\\ \end{equation}$

You can use the Ampere's Law

$\begin{equation}\\\oint_L B.dl\\ \end{equation}$ = $I_{in}$ μ

Where $I_{in}$ : Current passing through the window

μ : Free space’s magnetic permeability

μ = 4πx $10^{-7} T.m.A^{-1}$

Then

$\begin{equation}\\\oint_L B.dl\\ \end{equation}$ = (3-5)4πx $10^{-7}$

$\begin{equation}\\\oint_L B.dl\\ \end{equation}$ = -8πx $10^{-7}$

5 0

3 years ago