Answer:
Havent seen this one before but the explanation should help you out :)
Explanation:
There are only three atomic bonds.
Ionic bonding.
Covalent bonding.
Metallic bonding.
Answer:
v = 8.90 km/h
Explanation:
In order to calculate the maximum collision speed of the 1200kg car, you take into account that the the kinetic energy of the car when it has a speed v, is equal to the potential elastic energy of the spring when it is maximum compressed.
Then, you use the following equation:
(1)
M: mass of the car = 1200kg
v: maximum collision speed of the car = ?
k: spring constant = 1.5MN/m = 1.5*10^6 N/m
x: maximum compression supported by the spring = 7.0cm = 0.070m
You solve the equation (1) for v and replace the values of the other parameters:
In km/h you obtain:
The maximum collision that the car can support is 8.90km/h
Answer:
The ball is in the air for approximately 0.45 seconds
Explanation:
We only need to use the information on the height of the table to find the time, since the vertical movement is a movement under the acceleration of gravity, and with no initial velocity in the y-direction (recall that the ball rolls off a 1.0 m high table)
therefore the equation of motion for the vertical component is:
which for our information becomes:
Answer:
The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
Explanation:
Given that,
Amplitude = 0.08190 m
Frequency = 2.29 Hz
Wavelength = 1.87 m
(a). We need to calculate the shortest transverse distance between a maximum and a minimum of the wave
Using formula of distance
Where, d = distance
A = amplitude
Put the value into the formula
Hence, The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.