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3 years ago

What device is used to protect bulidings from lightning strikes

Physics

1 answer:

miv72 [106K]3 years ago

3 0

Ground rods- Log thick heavy rods buried deep into the earth around a protective structure

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13. An aircraft heads North at 320 km/h rel:

AURORKA [14]

The velocity of the aircraft relative to the ground is 240 km/h North

Explanation:

We can solve this problem by using vector addition. In fact, the velocity of the aircraft relative to the ground is the (vector) sum between the velocity of the aircraft relative to the air and the velocity of the air relative to the ground.

Mathematically:

$v' = v + v_a$

where

v' is the velocity of the aircraft relative to the ground

v is the velocity of the aircraft relative to the air

$v_a$ is the velocity of the air relative to the ground.

Taking north as positive direction, we have:

v = +320 km/h

$v_a = -80 km/h$ (since the air is moving from North)

Therefore, we find

$v'=+320 + (-80) = +240 km/h$ (north)

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

7 0

4 years ago

You dip a wire loop into soapy water (n = 1.33) and hold it up vertically to look at the soap film in white light. The soap film

Gnesinka [82]

Answer:

the thickness of the soap film is 127.82 nm or 130 nm

Explanation:

Given the data in the question;

n = 1.33

λ $_t$ = 680 nm = 680 × 10⁻⁹ m

m = 1 and β = 0

When we see the red fringe, its a point of maximum reflection

hence, for interference with a thin soap film, we say;

2 × n × d × cos( β ) = ( m - 0.5) × λ $_t$

so we substitute in our given values;

2 × 1.33 × d × cos( 0 ) = ( 1 - 0.5) × ( 680 × 10⁻⁹ )

2.66 × cos( 0 ) × d = 0.5 × ( 680 × 10⁻⁹ )

2.66 × 1 × d = 3.4 × 10⁻⁷

d = ( 3.4 × 10⁻⁷ ) / 2.66

d = 127.82 × 10⁻⁹ m

d = 127.82 nm ≈ 130 nm

Therefore, the thickness of the soap film is 127.82 nm or 130 nm

4 0

3 years ago

A 30 ky child running at 7 m/s jumps onto a 10 kg sled which was initially at rest. What will be the

Ede4ka [16]

Hope this helps. If you need clarification just ask me!

7 0

3 years ago

A ball rolls along the floor with a constant velocity of 2.3 m/s. How far will it travel after 15 seconds.

marissa [1.9K]

Answer:

0. 153m

Explanation:

displacement= velocity/ time

S = 2.3 m/s / 15s

S = 0. 153m

5 0

4 years ago

At what angle should the axes of two polaroids be placed so as to reduce the intensity of the incident unpolarized light to 13.

prohojiy [21]

Answer:

θ = 66.90°

Explanation:

we know that

$I= \frac{I_0}{2}cos^2\theta$

I= intensity of polarized light =1

I_o= intensity of unpolarized light = 13

putting vales we get

$1= \frac{13}{2}cos^2\theta$

⇒ $\theta=cos^{-1} \sqrt{\frac{1}{6.5} }$

therefore θ = 66.90°

5 0

3 years ago