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34kurt
3 years ago
12

Name two example of oxygenase

Chemistry
1 answer:
Nataly_w [17]3 years ago
4 0
Air sksksks and I oop-
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How is the life cycle of a star similar to that of a human?
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A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. how much calcium is contained in 45.0 g of c
kolbaska11 [484]

In a sample of pure calcium fluoride of mass 15.0 g, 7.70 g of calcium is present. First convert the mass into number of moles as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass.

Molar mass of Ca is 40 g/mol, putting the values,

n=\frac{7.70 g}{40 g/mol}=0.1925 mol

Similarly, molar mass of CaF_{2} is 78.07 g/mol thus, number of moles will be:

n=\frac{15.0 g}{78.07 g/mol}=0.1921 mol.

Thus, 0.1921 mol of CaF_{2} have 0.1925 mol of Ca, or 1 mole of CaF_{2} will have approximately 1 mole of Ca.

Now, mass of Ca needs to be calculated in 45.0 g of CaF_{2}. Converting mass into number of moles first,

n=\frac{45.0 g}{78.07 g/mol}=0.5764 mol

Thus, number of moles of Ca will also be 0.5764 mol, converting number of moles into mass,

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6 0
3 years ago
If I have an unknown quantity of gas at a pressure of 380 mmHg, a volume of 25 L, and a temperature of
Bess [88]

Answer:

                     0.5077 moles

Explanation:

Data Given:

                Moles  =  n  =  <u>???</u>

                Temperature  =  T  =  300 K

                 Pressure  =  P  =  380 mmHg = 0.50 atm

                 Volume  =  V  =  25 L

Formula Used:

Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,

                 P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                 n  =  P V / RT

Putting Values,

                 n  =  (0.50 atm × 25 L) / (0.082057 atm.L.mol⁻¹.K⁻¹ × 300 K)

                 n  = 0.5077 moles

6 0
3 years ago
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