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diamong [38]
3 years ago
11

Classify carbon dioxide:

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
4 0
Carbon dioxide is a compound.
 
It is a combination of carbon (C) and oxygen (O) --> CO2




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BASIC CALCULATIONS IN SPECTROSCOPY
gayaneshka [121]

Answer: 25%

Explanation:  

1. Transmittance, T= P/P0  

Where P = light exiting the cell

           P0 = light entering the cell

Therefore %T =  P/P0 ×100

           = 50/200×100

=25%

2. Absorbance, A= -log(T)

But T= 0.25

Therefore A= -log(0.25)

                  = 0.6020

7 0
3 years ago
Given the formula representing a compound: What is the IUPAC name of this compound?
Drupady [299]

Answer:

2,2- dichloro-heptane

Explanation:

The IUPAC name of the compound is 2,2-dichloro-heptane

6 0
3 years ago
I need help I know it isnt A
inna [77]
It is B. Thank you later please and do good on the test!
5 0
3 years ago
Read 2 more answers
What does ‘ aq ’ stand for in chemistry
Genrish500 [490]

Solid (s), liquid (l), gas (g), or dissolved in water (aq). aq is called aqueous which comes. from the Latin word aqua meaning water. If you do not know the state of a substance. see melting and boiling points.
7 0
3 years ago
A sample of xenon gas collected at a pressure of 948 mm Hg and a temperature of 283 K has a mass of 128 grams. What is the volum
disa [49]

Answer:

V = 1.84 × 10³ L

Explanation:

You need to use the Ideal Gas Law and solve for volume.

PV = nRT

V = nRT/P

First, you need to convert the pressure to atm.

1 atm = 760 mm Hg

948/760 = 1.247 atm

Next, convert grams of xenon to moles.  The molar mass is 131.293 g/mol.

128/131.293 = 0.975 mol

You now have all of the values needed.

P = 1.247 atm

n = 0.975 mol

R = 8.314 J/mol*K

T = 283 K

Plug the values in and solve.

V = nRT/P

V = (0.975 × 8.314 × 283)/1.247

V = 1.84 × 10³ L

The volume of the sample will be 1.84 × 10³ L.

7 0
3 years ago
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