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DedPeter [7]
3 years ago
10

Eight more than twice a number is fifty

Mathematics
2 answers:
krok68 [10]3 years ago
8 0
2x + 8 = 50 

Subtract 8 from both sides

2x = 42

Divide both by 2 

x = 21
emmasim [6.3K]3 years ago
3 0

Let, the number = x

then, 2x+8 = 50

2x = 42

x = 21

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1<br>Prove that<br>1: sin/1-cot + cos/1-tan=cos+sin​
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Answer:

have:

\frac{sin}{1-cot}+\frac{cos}{1-tan}\\\\=\frac{sin}{1-\frac{cos}{sin} }+\frac{cos}{1-\frac{sin}{cos} }\\\\=\frac{sin^{2} }{sin-cos}+\frac{cos^{2} }{cos-sin} \\\\=\frac{sin^{2} }{sin-cos}-\frac{cos^{2} }{cos-sin}\\\\=\frac{sin^{2}-cos^{2}  }{sin - cos}\\\\=\frac{(sin-cos)(sin+cos)}{sin-cos}\\\\=sin+cos

Step-by-step explanation:

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8 0
3 years ago
Mapping diagram: Is it a function? (yes /<br> no<br> ) Why or why not?
sashaice [31]
<h3>It is a function</h3>

Why? Because each input maps to <u>exactly one</u> output. The input oval represents the domain (set of all possible inputs). The output oval is the range, which is the set of all possible outputs. If we had something like the input 0 mapping to the outputs 2 and 4 at the same time, then we wouldn't have a function.

5 0
2 years ago
Solve the right triangle. Round decimal answers to the nearest tenth.
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8 0
3 years ago
Can someone please help with this ?
creativ13 [48]

Answer:     -9n+20

This is the same as 20-9n

================================================

Explanation:

The jump from 11 to 2 is "minus 9"

The jump from 2 to -7 is also "minus 9".

Assuming this pattern continues on, we have an arithmetic sequence with

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  • d = -9 = common difference

The nth term can be found like so

a_n = a + d(n-1)\\\\a_n = 11 + (-9)(n-1)\\\\a_n = 11 -9n + 9\\\\a_n = -9n+20\\\\

Let's check the answer by trying n = 3

a_n = -9n+20\\\\a_3 = -9*3+20\\\\a_3 = -27+20\\\\a_3 = -7\\\\

This shows the third term is -7, which matches what the original sequence shows. The answer is partially confirmed. I'll let you check the other values of n. You should get 11 when trying n = 1, and you should get 2 when trying n = 2.

4 0
2 years ago
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