(20*1000)÷(molecular weight of H3po4*50)
The half-life of a radioactive compound is the time taken for that said isotope to decay or disintegrate so that only half of the initial atoms remain in that compound. During the decay process, the isotope will give off energy and matter, and the way to depict this is indicated by t 1/2.
Answer:
the answer is d
Explanation:
It migrates to coastal areas during the winter months to catch fish.
The red blood cell will shrink.
In salt solution, the water potential is a lot lower than the cell cytoplasm. In that way, water molecules will flow from the inside of the cell to the salt solution by osmosis. The red blood cell will loose so much water that it shrinks.
But we don't have to worry about that because this won't occur inside our body, since there is mechanism in our body that regulates the concentration of blood.
According to the second-order rate constant formula:
K t = 1/[At] - 1/[Ao]
when k is the rate constant = 0.035 (given missing in your question)
and t is the time = 190 sec
Ao is the initial concentration of X = 0.35 m
by substitution:
0.035 * 190 sec = 1/[At] - 1/0.35
∴ [At] = 0.11 m
∴ the concentration after 190 sec = 0.11 m
