The value of Ka for acetylsalicylic acid will be calculated as Ka=(x+a)²/x.
<h3>What is Ka?</h3>
Ka is known by the name of acid dissociation constant and for weak acid HA at equilibrium Ka will be calculated as:
Ka = [H⁺][A⁻] / [HA]
Chemical equation with ICE table for the acetylsalicylic acid will be shown as:
C₉H₈O₄(aq) + H₂O(l) ⇄ C₉H₇O₄(aq) + H₃O⁺(aq)
Initial: x 0 0
Change: -a +a +a
Equilibrium: x-a x+a x+a
So, Ka for acetylsalicylic acid will be calculated by putting values on the above equation as:
Ka = [x+a][x+a] / [x-a]
Value of a is negligible as compared to the value of x of acetylsalicylic acid so the term x-a becomes x and equation will be written as:
Ka = (x+a)² / x
By knowing the all values of concentration we can calculate the value of Ka.
Hence Ka value for acetylsalicylic acid will be calculated by using the formula as Ka = (x+a)² / x.
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Answer:
P = 20atm
Explanation:
P1 = 10atm
T1 = 10K
P2 = ?
T2 = 20K
This question requires the use of pressure law which states that the pressure of a fixed mass of gas is directly proportional to its temperature provided its volume remains constant
Mathematically,
P = kT, k = P / T
P1 / T1 = P2 / T2 = P3 / T3=........=Pn / Tn
P1 / T1 = P2 / T2
P2 = (P1 × T2) / T1
P2 = (10 × 20) / 10
P2 = 20atm
The final pressure of the gas is 20atm
Answer: Decreased temperatures and increased salinity. Colder water is denser than warm water and the higher the salinity of water the denser it is.
Complete Question
A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 74.0 wide. The biologist estimates she will need 2600 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to significant digits.
Answer:
The pressure required is 
Explanation:
Generally the volume of a sphere is mathematically denoted as

Substituting 


Converting to Liters


Assume that the pressure at which the air is given to the diver is 1 atm when the air was occupying a volume of 2600L
So
From Charles law

Substituting
,
,
, and making
the subject we have


