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2 years ago

PLS HELP

Chemistry

2 answers:

alexandr1967 [171]2 years ago

5 0

Answer:

Explanation:

A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1

Simora [160]2 years ago

5 0

Someone put the answer btw

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890J of heat are applied to a piece of aluminum, causing a 4.6°C increase in its temperature. The specific heat of aluminum is 0

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The answer would be C 214g

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2 years ago

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3 years ago

The fuel used to power the booster rockets on space shuttles is a mixture of aluminum metal and ammonium perchlorate. The follow

pishuonlain [190]

Answer:

Therefore 373 mole of Al produce 746 mole of water.

Explanation:

Given reaction is

3 Al+3NH₄ClO₄→Al₂O₃+AlCl₃+3NO+6H₂O

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Therefore

3 mole of Al produce 6 mole of water.

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= 746 mole of water.

Therefore 373 mole of Al produce 746 mole of water.

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2 years ago