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Answer:
is dissociation constant and the value of
is 4.98.
Explanation:
The pH of the solution = 2.95 M
..[1]
Concentration of unknown monoprotic acid = C = 0.1224 M
Initially
C 0 0
At equilibrium
(C-x) x x
The expression of a dissociation reaction can be written as;
( from [1])
The value of :
is dissociation constant and the value of
is 4.98.
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The value of ideal gas constant (R) in Joule is 8.314 Joule . Now the given expression is 1.00 J. g
. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C = (-)
g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.