A: BE has more ionization energy than LI
B: CA has more ionization energy than BA.
C: NA has more ionization energy than K
D: AR has more ionization energy than P
E: CI has a more ionization energy than SI
F: LI has more ionization energy than K
If any of these are wrong feel free to correct me in the comments.
Answer:
The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.
Explanation:
The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:
n = 1.375x10⁻⁵ mol
The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):
1.375x10⁻⁵ mol _________ 19.9 units
x _________ 25.2 units
x = 1.741x10⁻⁵mol
Finally, we can calculate the Cu²⁺ concentration :
C = 1.741x10⁻⁵mol / 0.025 L
C = 6.964x10⁻⁴ M
Pretty sure it's D. El Nino but not positive.
Answer: Hydrogen bonds
Explanation: Hydrogen bonds allow two molecules to link together temporarily. Water molecules are made up of two hydrogen atoms and one oxygen atom, held together by polar covalent bonds.
<span>The electron configuration that represents a violation of the pauli exclusion principle is:
</span><span>1s: ↑↓
2s: ↑↑
2p: ↑</span>
The Pauli exclusion principle refers to the quantum mechanical rule which expresses that at least two indistinguishable fermions (the particles with half-integer spin) can't involve a similar quantum state inside a quantum framework all the while.
