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3 years ago

Chem. Assignment I need help...with answers 1-6 thanks

Chemistry

1 answer:

Anna11 [10]3 years ago

8 0

Answer:

1. an educated guess

2. data

3. what changes in experiment

4. what stays the same in both groups

5. the group where nothing changes, normal

6. group with independent variable, what's being tested

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How do protons, neutrons, and electrons differ in charge?

Semenov [28]

Answer: Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.

Explanation:

7 0

3 years ago

The Tacoma narrows bridge collapsed due to?

vovangra [49]

Explanation: aeroflastic flutter

8 0

4 years ago

Read 2 more answers

In the equation:

Ksenya-84 [330]

Answer:

B) 16 g

Explanation:

2H₂ + O₂ → 2H₂O

First we convert 4 moles of O₂ into moles of H₂, using the stoichiometric coefficients of the balanced reaction:

4 mol O₂ * $\frac{2molH_2}{1molO_2}$ = 8 mol H₂

Finally we convert 8 moles of H₂ into grams, using its molar mass:

8 mol H₂ * 2 g/mol = 16 g

Thus, the correct answer is option B).

6 0

3 years ago

Tarnish on copper is the compound CuO. A tarnished copper plate is placed in an aluminum pan of boiling water. When enough salt

oksian1 [2.3K]

Answer:

The standard cell potential is 2.00 V

Explanation:

Step 1: Data given

Cu is cathode because of higher EP

Al3++3e−→Al E∘=−1.66 V anode

Cu2++2e−→Cu E∘=0.340 V cathode

Step 2: Balance both equations

2*(Al → Al3+-3e−) E∘=1.66 V

3*(Cu2++2e−→Cu) E∘=0.340 V

Step 3: The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+ → 2Al3+ + 3Cu

Step 4: Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

4 0

3 years ago

What is the ph of a 0.0055 m ha (weak acid) solution that is 8.2% ionized?

Trava [24]

Answer is: pH value of weak is 3.35.
Chemical reaction (dissociation): HA(aq) → H⁺(aq) + A⁻(aq).
c(HA) = 0.0055 M.
α = 8.2% ÷ 100% = 0.082.
[H⁺] = c(HA) · α.
[H⁺] = 0.0055 M · 0.082.
[H⁺] = 0.000451 M.
pH = -log[H⁺].
pH = -log(0.000451 M).
pH = 3.35.
pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.

3 0

3 years ago