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SIZIF [17.4K]
3 years ago
13

Suppose you are helping mccarthy choose her sample sites. you have the resources to conduct the study at only 4 sites. pick the

4 sites that allow all 4 possible treatment combinations, while controlling for sunlight. drag a check mark to each site you would use, and drag xs to the sites you would not use. you should end up placing 4 check marks and 8 xs. labels can be used more than once.
Chemistry
1 answer:
VARVARA [1.3K]3 years ago
4 0

I dont know the answer

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How many molecules of N2O4 are in 76.3g N2O4? The molar mass of N2O4 is 92.02 g/mol.
Murrr4er [49]

Answer:

4.99*10²³ molecules of N₂O₄ are in 76.3 g of N₂O₄

Explanation:

Avogadro's Number is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.

You know that the molar mass of N₂O₄ is 92.02 g/mol, and you have 76.3 g. Then you can apply the following rule of three: 92.02 grams are present in 1 mole of the compound, 76.3 grams in how many moles are they?

amount of moles= \frac{76.3 grams*1 mole}{92.02 grams}

amount of moles= 0.83 moles

Then, you can apply another rule of three: if by definition of Avogadro's number 1 mole of the compound has 6.023*10²³ molecules, 0.83 moles of the compound, how many molecules will it have?

amount of molecules= \frac{0.83 moles*6.023*10^{23}molecules }{1 mole}

amount of molecules= 4.99*10²³

<u><em>4.99*10²³ molecules of N₂O₄ are in 76.3 g of N₂O₄</em></u>

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it has less tightly bound electrons, is able to lose electron easily as compare to metal B at it has 4 unpaired electron in 3d sub-shell.

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I hope this helps.

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