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s344n2d4d5 [400]
3 years ago
12

A compound with a molar mass of 102.133 g/mol contains an element with a subscript of 5 . the element is 58.80 g per 100.0 g com

pound. determine the molar mass (g/mol) of the element.
Chemistry
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

12.0108408

Explanation:

Denote the element with a letter like say X. Since it has a subscript of 5, then, X5.

Molecular mass=102.133g/mol.

% of X in compound =58.8/100

=0.588

Mass of X in the compound = 0.588*102.133 ( the % of X in compound * molar mass of compound)

= 60.054204

X5=60.054204

Then element X has a mass of 60.054204/5=12.0108408

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Suppose 2.4 g of Mg reacts with 10.0 g of O2, to create magnesium oxide. How much magnesium oxide is produced?
o-na [289]

Answer:

3.98 g

Explanation:

Step 1. Write the balanced chemical reaction. In this case, magnesium reacts with oxygen to produce magnesium oxide:

2~Mg(s) + O_2 (g)\rightarrow 2~MgO (s)

\\

Step 2. Calculate the number of moles of magnesium:

n_{Mg} = \frac{2.4~g}{24.305~g/mol} = 0.0987~mol

\\

Step 3. Calculate the number of moles of oxygen:

n_{O_2} = \frac{10.0~g}{32.00~g/mol} = 0.3125~mol

\\

Step 4. Identify the limiting reactant comparing the equivalents. Equivalent of Mg:

eq_{Mg} = \frac{0.0987~mol}{1} = 0.0987~mol

Equivalent of oxygen:

eq_{O_2} = \frac{0.3125~mol}{2} = 0.15625~mol

Therefore, Mg is the limiting reactant.

\\

Step 5. According to the stoichiometry of this reaction:

n_{Mg} = n_{MgO} = 0.0987~mol

\\

Step 6. Convert the number of moles of MgO into mass:

m_{MgO} = 0.0987~mol\cdot 40.304~g/mol = 3.98~g

5 0
3 years ago
The melting points of canola oil, corn oil, sunflower oil, and peanut oil are 10°C, –11°C, –17°C, and –2°C. If you cool a mixtur
patriot [66]
You can separate out the canola oil easily, because it has cooled down enough to turn back into a solid.
8 0
3 years ago
Empirical formula for 6. 63.52% Fe, 36.48% S
emmasim [6.3K]
The empirical formula for this would be FeS
8 0
3 years ago
Estimate the surface-to-volume ratio of a C60 fullerene by treating the molecule as a hollow sphere and using 77pm for the atomi
AleksAgata [21]

Answer:

The surface-to-volume ratio of a C-60 fullerene is 3:77.

Explanation:

Surface area of sphere = S=4\pi r^2

Volume of the sphere = V=\frac{4}{3}\pi r^3

where : r  = radius of the sphere

Radius of the C-60 fullerene sphere = r = 77 pm

Surface area of the C-60 fullerene = S=4\pi (77 pm)^2...[1]

Volume area of the C-60 fullerene = V=\frac{4}{3}\pi (77 pm)^3..[2]

Dividing [1] by [2]:

\frac{S}{V}=\frac{4\pi (77 pm)^2}{\frac{4}{3}\pi (77 pm)^3}

=\frac{3}{77}

The surface-to-volume ratio of a C-60 fullerene is 3:77.

7 0
3 years ago
a sample of sucrose was burned in a calorimeter, and 41,600 joules oh heat energy were released. which statement is true about t
Gala2k [10]

It absorbed 41,600 joules.

Explanation:

If the sample of sucrose burnt in the calorimeter releases 41600Joules of heat, then the water in the calorimeter will absorb 41600J.

 The heat lost by burning the sucrose in the calorimeter is also the heat gained by the water therein.

A calorimeter is a device by prevents heat loss to the environment in any form.

It is specially designed to minimize heat loss by conduction, convection radiation.

Therefore, since no heat is lost, the heat released by burning the sucrose is used in heating the water there.

learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

5 0
3 years ago
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