When you float an ice cube in water, you notice that 90% of it is submerged beneath the surface. Now suppose you put the same ic
1 answer:
Answer:
more than 90%
Explanation:
In the unknown liquid the buoyant force and weight relation is
It can be seen that if the density decreases the buoyant force decreases.
If the object is already 90% submerged in water then, if the other liquid has density less than that of water the object will be submerged more than 90%.
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Answer:
Explanation:
Since this is not parabolic motion, it is one-dimensional motion. Very simple. What we are given is
mass: 15.0 kg
initial velocity: 2.0 m/s
acceleration: .75 m/s/s
time: 6.0 seconds
Since we are looking for final velocity, the equation we need for this is
v = v0 + at that says final velocity is equal to the initial velocity plus the acceleration of the object times how long it travels. We don't have a need for the mass here at all.
Notice that one of the seconds labels to the right of the plus sign cancel out, leaving us with like units...which we HAVE to have if we want to add.
Simplifying a bit gives us
v = 2.0 m/s + 4.5 m/s so
v = 6.5 m/s
Answer and explanation:
A.
Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)
B.
In muon rest frame it travels Zero meters
C.
Distance, d = Velocity, v * Time, s
D.
Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame
that is same as in part C which is 594m
E.
Using lorentz contraction
In the rest frame of someone standing on the mountain
the distance is given by
d' = 258.92m
F.
in the rest frame of someone standing on the mountain,
muon moves straight down