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Anni [7]
3 years ago
9

Two resistors connected in series (R1, R2) are connected to two resistors that are connected in parallel (R3,R4). The series-par

allel combination is connected to a battery. Each resistor has a resistance of 10.00 Ohms. The wires connecting the resistors and battery have negligible resistance. A current of 2.00 A runs through resistor R1. What is the voltage supplied by the voltage source?
Physics
1 answer:
Debora [2.8K]3 years ago
6 0

Explanation:

R1=R2=R3=R4=10 ohms

V=IR

V=2.10

V=20v

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nadya68 [22]
Momentum - mass in motion
P=MV
P=(15,000 kg)(2.5 m/s)
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Hope this helps
5 0
3 years ago
An 800-kHz radio signal is detected at a point 2.7 km distant from a transmitter tower. The electric field amplitude of the sign
dimaraw [331]

Answer:

Option D is correct: 170 µW/m²

Explanation:

Given that,

Frequency f = 800kHz

Distance d = 2.7km = 2700m

Electric field Eo = 0.36V/m

Intensity of radio signal

The intensity of radial signal is given as

I = c•εo•Eo²/2

Where c is speed of light

c = 3×10^8m/s

εo = 8.85 × 10^-12 C²/Nm²

I = 3×10^8 × 8.85×10^-12 × 0.36²/2

I = 1.72 × 10^-4W/m²

I = 172 × 10^-6 W/m²

I = 172 µW/m²

Then, the intensity of the radio wave at that point is approximately 170 µW/m²

7 0
3 years ago
See how a block and tackle system can increase your mechanical advantage. You will need two broomsticks, a rope, and two helpers
Lisa [10]

Answer:

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4 0
3 years ago
The distance from the Earth to the Sun is known as an astronomical unit (AU). This distance is also equal to 1.496e+011 m. Neptu
Lerok [7]

Answer:

The distance from the Sun to Neptune is 29,41 AU.

Explanation:

We know, from the sentence, that the orbit of Neptune has an average diameter around 8.80*10⁹km.

Now, we can calculate the radius of this orbit, which is equivalent to the distance from thsi planet to the Sun. Let's recall tha the radius is the half of the diameter.

R=\frac{8.80\cdot 10^{9}}{2}=4.4\cdot 10^{9}km=4.4\cdot 10^{12}m

Ok, we know that 1.496*10¹¹m is an AU, therefore we have:

4.4\cdot 10^{12}m\cdot \frac{1 AU}{1.496\cdot 10^{11}}=29,41 AU

Finally, the distance R is 29,41 AU.

I hope it helps you! :)

7 0
3 years ago
Plz help asap.
stich3 [128]

Answer:

In a primary cell, two electrodes (one of copper and other of zinc) of metal atoms are used. These electrodes are dipped in an electrolyte solution that causes the metals to produce their respective positive and negative ions.

In this way, the flow of charges takes place and supply the electricity to the source.

Unlike a primary cell, a dry cell contains paste of an electrolyte instead of the solution. The contents of electrolyte paste react with each other through a chemical process and convert the chemical energy into electrical energy.

5 0
3 years ago
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