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2 years ago

Which example nest represents balanced forces ???

Physics

1 answer:

n200080 [17]2 years ago

5 0

Answer:

an elevator stopped on the third floor a basketball shot into a hoop a sled sliding down a snowy hill a tow truck pulling a car out of a ditch

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On a vacation flight, you look out the window of the jet and wonder about the forces exerted on the window. Suppose the air outs

Anettt [7]

Answer:

The pressure difference is 25.8kPa while the force exerted on the window by air pressure is 3.02 kN

Explanation:

Using the Bernoulli's equation

$P_{in}+\frac{1}{2}\rho v_{in}^2=P_{out}+\frac{1}{2}\rho v_{out}^2$

Here

Pin-Pout is the pressure difference which is to be calculated.

ρ is the density of air whose value is 1.29 kg/m^3

vin is the velocity of air inside which is 0 m/s

vout is the velocity of air outside which is 200 m/s

Substituting values in the above equation yields

$\Delta P=P_{in}-P_{out}\\\Delta P=\frac{1}{2}\rho (v_{in}^2-v_{out}^2)\\\Delta P=\frac{1}{2}\times 1.29 ( 200^2-0)\\\Delta P=25.8 kPa$

So the pressure difference is 25.8kPa.

As force is given by

$F=PA\\F=\Delta P A\\$

Here

ΔP is the pressure difference calculated above
A is the area of the window given as

$A=L \times W\\A=0.26 \times 0.45\\A=0.117 m^2$

Now force is

$F=\Delta P A\\F=25.8 \tiems 10^3 \times 0.117\\F=3.02 kN$

So the force exerted on the window by air pressure is 3.02 kN

6 0

2 years ago

What is the acceleration of a racing car if it's speed is increased uniformly from 44 m /s to 66 m / s over an 11 second period

jolli1 [7]

Answer:

the acceleration of the race car is 2 m/s²

Explanation:

Given;

initial velocity of the race car, u = 44 m/s

final velocity of the race car, v = 66 m/s

time of motion of the race car, t = 11 s

The acceleration of the race car is calculated as;

$a = \frac{v-u}{t} \\\\a = \frac{66-44}{11} \\\\a = 2 \ m/s^2$

Therefore, the acceleration of the race car is 2 m/s²

7 0

2 years ago

Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric

love history [14]

Answer:

Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?(D)

Explanation:

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