If one bulb goes out then all the others won't light up because electricity will be cut off. It's a disadvantage because in a parallel circuit if one bulb burns out all the others will still be on because they won't be affected. I hope I've helped you ☺
The first factor is wind speed, the second factor is wind duration, and the last factor is the fetch, the distance over which the wind blows without a change in direction.
all these factors determines the strength of a wave.
hope this helps :)
Answer:
2240.92365 m/s
Explanation:
= Mass of electron = ![9.11\times 10^{−31}\ kg](https://tex.z-dn.net/?f=9.11%5Ctimes%2010%5E%7B%E2%88%9231%7D%5C%20kg)
= Speed of electron = ![5.7\times 10^7\ m/s](https://tex.z-dn.net/?f=5.7%5Ctimes%2010%5E7%5C%20m%2Fs)
= Neutrino has a momentum = ![7.3\times 10^{-24}\ kg m/s](https://tex.z-dn.net/?f=7.3%5Ctimes%2010%5E%7B-24%7D%5C%20kg%20m%2Fs)
M = total mass = ![2.34\times 10^{-26}\ kg](https://tex.z-dn.net/?f=2.34%5Ctimes%2010%5E%7B-26%7D%5C%20kg)
In the x axis as the momentum is conserved
![Mv_x=m_1v_1\\\Rightarrow v_x=\dfrac{m_1v_1}{M}\\\Rightarrow v_x=\dfrac{9.11\times 10^{−31}\times 5.7\times 10^7}{2.34\times 10^{-26}}\\\Rightarrow v_x=2219.10256\ m/s](https://tex.z-dn.net/?f=Mv_x%3Dm_1v_1%5C%5C%5CRightarrow%20v_x%3D%5Cdfrac%7Bm_1v_1%7D%7BM%7D%5C%5C%5CRightarrow%20v_x%3D%5Cdfrac%7B9.11%5Ctimes%2010%5E%7B%E2%88%9231%7D%5Ctimes%205.7%5Ctimes%2010%5E7%7D%7B2.34%5Ctimes%2010%5E%7B-26%7D%7D%5C%5C%5CRightarrow%20v_x%3D2219.10256%5C%20m%2Fs)
In the y axis
![Mv_y=p_2\\\Rightarrow v_y=\dfrac{p_2}{M}\\\Rightarrow v_y=\dfrac{7.3\times 10^{-24}}{2.34\times 10^{-26}}\\\Rightarrow v_y=311.96581\ m/s](https://tex.z-dn.net/?f=Mv_y%3Dp_2%5C%5C%5CRightarrow%20v_y%3D%5Cdfrac%7Bp_2%7D%7BM%7D%5C%5C%5CRightarrow%20v_y%3D%5Cdfrac%7B7.3%5Ctimes%2010%5E%7B-24%7D%7D%7B2.34%5Ctimes%2010%5E%7B-26%7D%7D%5C%5C%5CRightarrow%20v_y%3D311.96581%5C%20m%2Fs)
The resultant velocity is
![R=\sqrt{v_x^2+v_y^2}\\\Rightarrow R=\sqrt{2219.10256^2+311.96581^2}\\\Rightarrow R=2240.92365\ m/s](https://tex.z-dn.net/?f=R%3D%5Csqrt%7Bv_x%5E2%2Bv_y%5E2%7D%5C%5C%5CRightarrow%20R%3D%5Csqrt%7B2219.10256%5E2%2B311.96581%5E2%7D%5C%5C%5CRightarrow%20R%3D2240.92365%5C%20m%2Fs)
The recoil speed of the nucleus is 2240.92365 m/s
Answer:
The focal length of the given spherical mirror is 20cm.
Explanation:
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