Answer:
ac = 27.22 m/s
Explanation:
ac=v^2/r
m=2500kg
v=35 m/s
Fc=mv^2/r
I'm not sure why you would need mass but I will solve for Fc aswell
Ac=35^2/45 = 1225/45= 27.22 m/s
Fc= 2500(27.22)=68050 N
Because each joint is capable of a different measure of its own range of motion
Refer to the diagram shown below
Given:
m = 2.8 kg, the mass of the bucket
a =3.1 m/s², the acceleration of the bucket
Therefore
W = 2.8*9.8 = 27.44 N, the weight of the bucket.
Let T = the tension in the rope.
From the free body diagram, the net force accelerating the bucket is
T - W = m*a
That is,
T = W + m*a
= 27.44 + 2.8*3.1 N
= 36.12 N
Answer: d. 36.1 N
Answer:
D: The particles emitted when atoms collide
Explanation:
Just took the test
Answer:
The energetic order third excited > seconds excited > first excited > ground
Explanation:
Bohr's atomic model includes an integer that is responsible for the quantization of energy
E = - 13.6 /n² eV
Where n is the so-called principal quantum number, it is an integer with values of
n = 1, 2, 3… inf
For n = 1 have the so-called ground state that is the one with the lowest energy, for the minus sign in the formula E1 = -13.6 eV
For n = 2 it is the first excited state has the most energy than the ground state,
E2 = 13.6 / 4 = -3.4eV
For n = 3 we have the second excited state, E3 = -13.6 / 9 = -1.5 eV
For n = 4 we have the third excited state, E4 = -0.85 eV
The energetic order of the states is
E4 > E3 > E2 >E1