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svetoff [14.1K]
3 years ago
9

What is the average speed of a boy who jogs 250 meters in 110 seconds

Physics
2 answers:
Ede4ka [16]3 years ago
8 0

2.27 mps repeating.

This is the last question ill ever answer here. Thanks for being the last.

topjm [15]3 years ago
5 0

his average speed is 2.27 meters per second  im sorry if im wrong

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The doppler effect is when objects are not moving?<br><br> True <br><br> False
SVETLANKA909090 [29]

Answer:

reviewing the statement we can say that it is FALSE

Explanation:

The Doppler effect is the change in the perceived frequency of a sound wave by the RELATIVE MOTION of the source and the observer.

This effect is very useful for finding the speed of an object.

When reviewing the statement we can say that it is FALSE

6 0
3 years ago
if the pressure on a gas increases, the volume of the gas also increases is that statement true or false?
Arada [10]
False, according to Boyle's law it's pressure increases, volume decreases
6 0
3 years ago
Two movers are pushing a large crate with a force of 60.0 n each. one pushes north, the other east. what is the equilibrant forc
romanna [79]
To get the solution you must need to draw a force triangle. Attach the head of the 60N north force arrow with the tail of the 60N east force arrow. The subsequent is the arrow connecting he tail and head of the two arrows. 
You get a right angled triangle, and the resultant is (60^2 + 60^2) ^0.5 = 84.85 N or 85 N northeast.
8 0
3 years ago
A glass tube 1 mm in diameter is dipped into glycerin. The density of the glycerin is 1260 kg/m3, surface tension is 6.3x10-2 N/
Sunny_sXe [5.5K]

Answer:

The capillary rise of the glycerin is most nearly  y  =  0.0204 \ m

Explanation:

From the question we are told that

  The diameter of the glass tube is  d =  1 \ mm =  0.001 \ m

   The density of glycerin is  \rho =  1260 \ kg /m^3

   The surface tension of the glycerin is \sigma   =  6.3 *10^{-2} \ N /m

The capillary rise of the glycerin is mathematically represented as

       y  =  \frac{4 * \sigma  *  cos (\theta )}{ \rho * g *  d}

substituting value  

       y  =  \frac{4 * 6.3 *10^{-2}  *  cos (0 )}{ 1260 * 9.8 *  0.001}

      y  =  0.0204 \ m

Therefore the height  of the glass tube  the glycerin was able to cover is

y  =  0.0204 \ m  

4 0
3 years ago
El conductor de un coche de 650 kg que va a 90 km/h frena y reduce su
Ivanshal [37]
A. 90km/h = 25 m/s
W=1/2mv^2
=1/2* 650* 25^2
= 203125(J)
b. v’= 90-50= 40km/h
= 100/9 m/s
W=1/2mv^2
=1/2*650*(100/9)^2
= 40123,45679
7 0
3 years ago
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