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The number of atoms of gold in the pure ring are 7.18 × 10²² atoms.
<h3>HOW TO CALCULATE NUMBER OF ATOMS?</h3>
The number of atoms in a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
The number of moles in the gold (Au) can be calculated by dividing the mass of gold by its molar mass (196.97g/mol).
no. of moles = 23.5g ÷ 196.97g/mol
no. of moles = 0.119mol
Number of atoms in Au = 0.119 × 6.02 × 10²³
no. of atoms = 7.18 × 10²² atoms.
Therefore, the number of atoms of gold in the pure ring are 7.18 × 10²² atoms.
Learn more about number of atoms at: brainly.com/question/15959704
The Law of Conservation of Matter states that matter cannot be created or destroyed. In a physical change, substances can change form, but the total mass remains the same.
To answer this question, you need to know the Avogadro number. To find the amount of sugar molecule from mol unit you need to multiply it by the Avogadro number.
The calculation should be like this: <span>0.734 mol * 6.02*10^23 molecule/ mol= 4.41 * 10^23 molecule</span>
Explanation:
Expression for rate of the given reaction is as follows.
Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]
Therefore, the reaction equations by putting the given values will be as follows.
![1.8 \times 10^{-5} = k[0.105]x [0.15]y](https://tex.z-dn.net/?f=1.8%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20k%5B0.105%5Dx%20%5B0.15%5Dy)
............. (1)
![7.2 \times 10^{-5} = k [0.105]x [0.30]y](https://tex.z-dn.net/?f=7.2%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20k%20%5B0.105%5Dx%20%5B0.30%5Dy)
........... (2)
![3.6 \times 10^{-5} = k [0.0525]x [0.30]y](https://tex.z-dn.net/?f=3.6%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20k%20%5B0.0525%5Dx%20%5B0.30%5Dy)
............ (3)
Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3) we get the value of x = 1.
Therefore, expression for rate of the reaction is as follows.
Rate = ![k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y](https://tex.z-dn.net/?f=k%5BHgCl_%7B2%7D%5Dx%20%5BC_%7B2%7DO%5E%7B2-%7D_%7B4%7D%5Dy)
Rate = ![k [HgCl2]1 [C_{2}O^{-2}_{4}]2](https://tex.z-dn.net/?f=k%20%5BHgCl2%5D1%20%5BC_%7B2%7DO%5E%7B-2%7D_%7B4%7D%5D2)
Hence, total order = 1 + 2 = 3
According to equation (1),
![1.8 \times 10^{-5} = k [0.105]1 [0.15]2](https://tex.z-dn.net/?f=1.8%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20k%20%5B0.105%5D1%20%5B0.15%5D2)
k = 
Thus, we can conclude that rate constant for the given reaction is .
