Answer:
first number is the correct answer
Molecular is every element present in the compound eg C2H6, empirical is the smallest whole number ratio of elements in a compound so that would be CH3 as you divide by the highest common factor. Some compounds only have 1 formula if they are simple or have no common factors. Eg methane, CH4 is its molecular and empirical because its the simplest whole number ratio and includes every element in the molecule
It causes the water to evaporate from the earths surface so that it can cycle through again
Answer:
b. The splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.
Explanation:
The spectrochemical series is an arrangement of ligands in increasing order of their magnitude of crystal field splitting.
Ligands that occurs towards the right in the series are called strong field ligands and they tend to cause a greater magnitude of crystal field splitting. Ligands that occur towards the left hand side in the series are called weak field ligands and they tend to cause a lesser magnitude of crystal field splitting.
Since Cl^- is a weak field ligand, it causes a lesser magnitude of d orbital splitting compared to ethylenediammine (en) which causes a greater magnitude of d orbital splitting.
Hence; the splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.
Answer: Object B will heat up more.
Explanation:
The formula for specific heat is as follows.
Q = 
Where,
Q = heat provided
m = mass
C = specific heat
= change in temperature
Now, both the objects have same mass and equal amount of heat is applied.
According to the formula, the equation will be as follows.
= 
= 
Cancel m from both sides, as mass is same. Therefore,
= 
Cancel out the initial temperature and put the values of specific heat, then the equation will be as follows.
= 
Therefore, from the above equation it can be concluded that the object with low specific heat will heat up more as its specific heat will be inversely proportional to its final temperature.
Hence, object B will heat up more.
