Beyond what point must an object be squeezed for it to become a black hole
1 answer:
Answer:
Condition
Explanation:
Basically black hole is an object from which light rays can not escape it means to go out from gravitational field , that body should thrown with speed greater then light.
Let's do some calculation
Gravitational potential at surface =
If we give kinetic energy equal to magnitude of Potential energy as on surface it will escape.
=
⇒
It will be more better for black hole if above ratio (analogous to density ) is more then above calculated
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To solve this problem we will use the Ampere-Maxwell law, which describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:
Where,
B= Magnetic Field
l = length
= Vacuum permeability
= Vacuum permittivity
Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to
Recall that the speed of light is equivalent to
Then replacing,
Our values are given as
Replacing we have,
Therefore the magnetic field around this circular area is
Answer:
G = 6,786 10⁻¹¹ m³ / s² kg
Explanation:
The law of universal gravitation is
F = G m M/ r²
Where G is the gravitational constant, m and M are the masses of the bodies and r is the distance from their centers
Let's use Newton's second law
F = m a
The acceleration is centripetal
a =
We replace
G m M / r² = m
G = r² / M
Let's replace and calculate
G = 2.7 10⁻³ (3.88 10⁸)² / 5.99 10²⁴
G = 6,786 10⁻¹¹ m³ / s² kg
Let's perform a dimensional analysis
[N m²/kg²] = [kg m/s² m² / kg²] = [m³ / s² kg]