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Ainat [17]
3 years ago
12

Beyond what point must an object be squeezed for it to become a black hole

Physics
1 answer:
Naddik [55]3 years ago
4 0

Answer:

Condition

\frac{m}{R} \geq \frac{c^{2} }{2*g}

Explanation:

Basically black hole is an object from which light rays can not escape it means   to go out from gravitational field , that body should thrown with speed greater then light.

Let's do some calculation

Gravitational potential at surface =-\frac{G*M*m}{R}

If we give kinetic energy equal to magnitude of Potential energy as on surface it will escape.

\frac{m*v^{2} }{2} =-\frac{G*M*m}{R}

⇒\frac{m}{R} =\frac{c^{2} }{2*G}

It will be more better for black hole if above ratio (analogous to density ) is more then above calculated

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Work = Distance x Mass

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Describe the astronomical achievement of Mesopotamia
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Consider an ideal monatomic gas of N particles with mass m in thermal equilibrium at a temperature T. The gas is contained in a
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Answer:

K.E.=\dfrac{3}{2}KT

Explanation:

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2 years ago
An underground gasoline tank can hold 1.07 103 gallons of gasoline at 52.0°F. If the tank is being filled on a day when the outd
Damm [24]

Answer:

1069.38 gallons

Explanation:

Let V₀ = 1.07 × 10³ be the initial volume of the gasoline at temperature θ₁ = 52 °F. Let V₁ be the volume at θ₂ = 97 °F.

V₁ = V₀(1 + βΔθ)  β = coefficient of volume expansion for gasoline = 9.6 × 10⁻⁴ °C⁻¹

Δθ = (5/9)(97°F -52°F) °C = 25 °C.

Let V₂ be its final volume when it cools to 52°F in the tank is

V₂ = V₁(1 - βΔθ) = V₀(1 + βΔθ)(1 - βΔθ) = V₀(1 - [βΔθ]²)

    = 1.07 × 10³(1 - [9.6 × 10⁻⁴ °C⁻¹ × 25 °C]²)

    = 1.07 × 10³(1 - [0.024]²)

    =  1.07 × 10³(1 - 0.000576)

    = 1.07 × 10³(0.999424)

    = 1069.38 gallons

7 0
3 years ago
PLZZ someone
Elena L [17]
The answer yr looking for would b true!
6 0
3 years ago
Read 2 more answers
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