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Arada [10]
3 years ago
7

A scientist has isolated a fatty acid that has 26 carbons. Most of the carbon atoms in the fatty acid chain are connected by sin

gle bonds, except there is a double bond between the number 3 and 4 carbons as well as the number 9 and 10 carbons. The only other elements in the compound are hydrogen and oxygen. Based on this information, the compound is a ________ fatty acid.
Chemistry
2 answers:
Olegator [25]3 years ago
6 0

Answer: ployunsaturated fatty acid

Explanation: The presence of two double bond in the fatty acid chain makes the compound poly unsaturated. Fatty acid can either be saturated or unsaturated. Mere presence of a single double bond makes it unsaturated.

igomit [66]3 years ago
3 0

Answer:

Polyunsaturated

Explanation:

A fatty acid is a compound that is derivative from a carboxylic acid. The chain of carbons can have since 4 carbons to more than 20 carbons. The bonds between carbons can be simple, which are called saturated bonds, or double, or triple, which is called unsaturated bonds.

When a fatty acid only has saturated bonds between carbons, it's called a saturated fatty acid. If there is only one unsaturated bond, it's called an unsaturated fatty acid, and if there are two or more unsaturated bonds, it's called polyunsaturated fatty acid.

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What is the empirical formula for a compound that is 83.7% carbon and 16.3% hydrogen?
zubka84 [21]
Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100 g solution)

C: 83.7% = 83,7 g 
H: 16.3% = 16.3 g 

Let us use the above mentioned data (in g) and values will be ​​converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

C:  \dfrac{83.7\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 6.975\:mol

H: \dfrac{16.3\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 16.3\:mol

We note that the values ​​found above are not integers, so let's divide these values ​​by the smallest of them, so that the proportion is not changed, let's see:

C:  \dfrac{6.975}{6.975} = 1

H:  \dfrac{16.3}{6.975} \approx 2.3

Note: So the ratio in the smallest whole numbers of carbon to hydrogen is 3:7, t<span>hus, the minimum or empirical formula found for the compound will be:
</span>
\boxed{\boxed{C_3H_7}}\end{array}}\qquad\checkmark

I hope this helps. =)
8 0
3 years ago
A ____________ always has the same chemical formula.
faltersainse [42]
<span>c. substance Is the best i think</span>
7 0
3 years ago
Why can't all mixtures be classified as solutions?
shusha [124]
D. Not all mixtures are heterogeneous
7 0
3 years ago
A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = \frac{10}{100}

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0
3 years ago
Read 2 more answers
Write a balanced formation equation at standard conditions for the compound HCN.
Aloiza [94]
The formation of hydrogen cyanide, HCN is formed by reacting hydrogen gas, carbon and nitrogen gas, expressed in the following expression below:

<span>½ H2 (g) + C (s) + ½ N2 (g) → HCN (g) ΔHof = 135 kJ
</span>
At standard conditions, hydrogen and nitrogen exist as gases while carbon is solid. This is also an endothermic reaction due to the positive <span>ΔHof</span>
7 0
3 years ago
Read 2 more answers
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