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Anton [14]
4 years ago
7

Which of the following statements about the conservation of momentum is not correct? Momentum is conserved for a system of objec

ts pushing away from each other. The total momentum of a system of interacting objects remains constant regardless of forces between the objects. Momentum is conserved when two or more interacting objects push away from each other. Momentum is not conserved for a system of objects in a head-on collision.
Physics
1 answer:
Olin [163]4 years ago
3 0

Answer:

wrong statement :  Momentum is not conserved for a system of objects in a head-on collision.

Explanation:

In a head on collision of two objects , two equal and opposite forces are created at the point of collision . These two forces create two impulses in opposite direction which results in equal and opposite changes in momentum in each of them . Hence net change in momentum is zero. In this way momentum is conserved in head on collision of two objects.

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Pick 3 safety rules in science that you think are important and explain what would happen if the rules were no followed. Used yo
IgorLugansk [536]

Answer:

Answer down below!

Explanation:

  1. Always wear goggles! This is to prevent chemicals or any other substance to get into your eyes. If this wasn't followed, more people could get hurt.
  2. Clean up afterwards! Its always better to clean up so someone else couldn't get hurt! If people don't follow this, it could be a mess and someone could get seriously injured.
  3. When smelling something, waft it to your face, and not get real close. This is to prevent getting chemicals into your body that could be poisonous. If people didn't folloe this, someone could be seriously sick.
7 0
3 years ago
A 10 kg package is delivered to your house. Use one complete sentence to describe an example of how work is done on the package
Mamont248 [21]

Answer:

Hey :)

Explanation:

Work is a net force applied through a distance in order to displace an object, commonly abbreviated as W.  A net force is the sum of all forces acting on an object. Work is mass times acceleration and distance so to find out the work you simply calculate the acceleration of the box being brought in. Next find the distance it was carried to get in the house. Then find out the mas of the box and finally multiply those sums together to get the amount of work put in to bring the package inside.

hope this helps :) xo

8 0
4 years ago
Please help me with this question
ladessa [460]

Answer:

conduction

Explanation:

5 0
4 years ago
Read 2 more answers
A student heats 100 g of aluminum to 60°C. He places it in 100 g of water at 20°C. Over time, what will most likely happen?
IgorLugansk [536]
-- Heat will flow out of the warm aluminum and into the cool water.

-- The temperature of the aluminum will fall and the temperature of the water will rise.

-- Eventually, everything in the container will settle at the same temperature, and temperatures will stop changing. 

-- The final "equilibrium" temperature will be a little less than 40°C (the average of 60° and 20°), because the specific heat of the aluminum is about 8% less than the specific heat of the water.  So when some quantity of heat flows from the aluminum to the water, the temperature of the water rises a little less than the temperature of the aluminum falls.
8 0
3 years ago
Determine the gravitational potential energy, in kJ, of 3 m3 of liquid water at an elevation of 30 m above the surface of Earth.
artcher [175]

Answer:

A. 873 kJ

B. -436.5 kJ

Explanation:

Parameters given:

Volume of water = 3m³

Density of water = 1000 kg/m³

Height above the earth, h = 30m

The gravitational potential energy, PE, is given as:

PE = m*g*h

Where m is mass and g is acceleration due to gravity.

Mass, m, can be obtained:

Density = mass/volume

Mass = density * volume

Mass, m = 3 * 1000 = 3000kg

=> Potential ENERGY, PE = 3000 * 9.7 * 30

PE = 873000 J = 873 kJ

B. If the height is decreased by 15m,

h = 30 - 15 = 15m

PE = 3000 * 9.7 * 15

PE = 436500 J = 436.5 kJ

Change in PE will be:

ΔPE = PEfinal - PEinitial

ΔPE = 436.5 - 873

ΔPE = -436.5 kJ

7 0
3 years ago
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