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3 years ago

How are the interference patterns for light through a double slit and light through a single slit similar yet different

Physics

1 answer:

xxMikexx [17]3 years ago

3 0

Answer: In double slit case, you need to understand superposition on waves emerging from dirrerent slit.

Explanation: When passing a single slit, wave spread in all directions.

In double slit waves with equal wavelength travel different path and distance

trey travel is different . Waves meet each other in different positions in different phases. If phase are same, waves have contructive interference, crests of waves meet in same point. Amplitudes of waves are added together. If waves are in opposite phases, sum of amplitudes

ame subtacted and this is destructive interference. Sum of amplitudes are zero.

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A moving particle is subject to conservative forces only. When its kinetic energy decreases by 10 J, what happens to its mechani

satela [25.4K]

Answer:

Its mechanical energy is the same.

Explanation:

If forces are only conservative, the mechanical energy will be the same.

It can be different if energy get transformed in another kind of energy like elastic energy for example, although the amount of energy is always the same.

If we just have mechanical energy not geting transformed we have:

Em=K+U

Em: Mechanical energy

K: Kinetic energý

U: Potential energy

Then if Kinetic energy decreases 10J, Potential energy will grow up 10J to keep the same amount of mechanical energy.

8 0

3 years ago

A 75-hp (shaft output) motor that has an efficiency of 91% is worn out and is replaced by a high efficiency 75-hp motor that has

ZanzabumX [31]

Answer:

The heat gain of the room due to higher efficiency is 2.84 kW.

Explanation:

Given that,

Output power of shaft = 75 hp

Efficiency = 91%

High efficiency = 95.4%

We need to calculate the electric input given to motor

Using formula of efficiency

$\eta=\dfrac{Work\ Output}{Work\ input}$

$Work\ Input =\dfrac{Work\ output}{\eta}$

$Work\ Input =\dfrac{75\times746}{0.91}$

$Work\ Input =61483.51\ W$

$Work\ Input = 61.48 kW$

We need to calculate the electric input

For, heigh efficiency

$Work\ Input_{inc} =\dfrac{75\times746}{0.954}$

$Work\ Input_{int} =58647.7\ W$

$Work\ Input_{int} = 58.64\ kW$

The reduction of the heat gain of the room due to higher efficiency is

$Q=Work\ Input-Work\ Input_{int}$

Put the value into the formula

$Q=61.48 -58.64$

$Q=2.84\ kW$

Hence, The heat gain of the room due to higher efficiency is 2.84 kW.

3 0

3 years ago

A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center

blagie [28]

Explanation:

Given that,

Mass of the particle, m = 4 kg

Speed of the particle, v = 2.5 m/s

The radius of the circle, r = 2 m

We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :

$L=mvr$

Substitute all the values,

$L=4\times 2.5\times 2\\\\L=20\ kg{\cdot}m^2s$

So, the angular momentum of the particle is 20 kg-m² s.

6 0

3 years ago

A uniform, solid, 1800.0 kgkg sphere has a radius of 5.00 mm. Find the gravitational force this sphere exerts on a 2.30 kgkg poi

iVinArrow [24]

Answer

given,

Mass of the solid sphere = 1800 Kg

radius of the sphere,R = 5 m

mass of the small sphere, m = 2.30 Kg

when the Point is outside the sphere the Force between them is equal to

$F = \dfrac{GMm}{r^2}$ when r>R

When Point is inside the Sphere

$F = \dfrac{GMm}{R^2}\ \dfrac{r}{R}$ when r<R

where r is the distance where the point mass is placed form the center

Now Force calculation

a) r = 5.05 m

$F = \dfrac{GMm}{r^2}$ [/tex]

$F = \dfrac{6.67\times 10^{-11}\times 1800\times 2.3}{5.05^2}$

F = 1.082 x 10⁻⁸ N

b) r = 2.65 m

$F = \dfrac{GMm}{R^2}\ \dfrac{r}{R}$

$F = \dfrac{6.67\times 10^{-11}\times 1800\times 2.3}{5.05^2}\ \dfrac{2.65}{5.05}$

$F = 5.68\times 10^{-9}\ N$

3 0

3 years ago

It is 40 degrees F outside. What is this in Celsius?

Vlad1618 [11]

It is 40 degrees F outside. What is this in Celsius?

4°C

7 0

3 years ago

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