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Alla [95]
3 years ago
14

What energy output objects work with the turbine

Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

maybe alternator..generator..

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Suppose that it takes 0.6 seconds for a mass on a spring to move from its highest position to its lowest position. What is the p
o-na [289]
The mass on the spring is bouncing. 

We would call it a wave-like motion, except that it all stays in the same place.  But, just like a wave, moving from the highest position to the lowest position
is one-half of a full wiggle. 

(The other half consists of moving from the lowest position back up to the
highest position, where it started from. 

So, half of the wave-like motion takes 0.6 seconds. 

A full cycle of the wave motion ... the actual period of the bounce,
is double that much time . . .
                                                   1.2 seconds.
6 0
4 years ago
If it takes 560 joules of work to move an object 10 meters what force was needed
Pavel [41]

Answer:

F = 56 N

Explanation:

  • Assuming that the applied force is parallel to the displacement, according to the definition of work, we can write the following expression for the force required:

       F = \frac{W}{\Delta x} =\frac{560J}{10m} = 56 N (1)

6 0
3 years ago
A beam of protons moves in a circle of radius 0.20 m. The protons move perpendicular to a 0.36-T magnetic field. (a) What is the
gregori [183]

Answer:

a) v=6.898\times 10^{6}\ m.s^{-1} is the speed of each proton

b) F_c=3.97\times 10^{-13}\ N

Explanation:

Given:

radius of path of motion, r=0.2\ m

we know charge on protons, q=1.6\times 10^{-19}\ C

magnetic field strength, B=0.36\ T

we've mass of proton, m=1.67\times 10^{-27}\ kg

a)

From the equivalence of magnetic force and the centripetal force on the proton:

F_B=F_C

q.v.B=\frac{m.v^2}{r}

q.B=\frac{m.v}{r}

where:

v = speed of the proton

(1.6\times 10^{-19})\times 0.36=\frac{1.67\times 10^{-27}\times v}{0.2}

v=6.898\times 10^{6}\ m.s^{-1} is the speed of each proton

b)

Now the centripetal force on each proton:

F_c=m.\frac{v^2}{r}

F_c=1.67\times 10^{-27}\times \frac{(6.898\times 10^6)^2}{0.2}

F_c=3.97\times 10^{-13}\ N

6 0
4 years ago
Question 4 Unsaved If element X has 93 protons, how many electrons does it have? Your Answer:
9966 [12]
It have 93 electrons
8 0
4 years ago
What is the mass of a soda can on a triple beam balance
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It depends on the kind of soda can
6 0
3 years ago
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